Answer:
0.823 Nm
Explanation:
current, i = 100 A
radius, r = 10 cm
Angle between the normal and the magnetic field, θ = 30°
Magnetic field, B = 0.524 T
Torque is defined as the
Torque = 0.823 Nm
Thus, the torque is 0.823 Nm.
Answer:
nice, kind, and listens to the golden rule.
Explanation:
thats a person with good qualities.
1134000J
Use the formula for kinetic energy K= 1/2*m*v^2
K=(1120*45^2)/2=1134000 Joule
<h3><u>Answer;</u> </h3>
= 0.03066 m
<h3><u>Explanation;</u></h3>
Work done or energy by a spring or an elastic material is given by the formula;
Potential energy = 1/2 kx²
Where, k is the spring constant and x is the distance stretched.
Therefore;
47 J = 1/2 (100000 n/m) x²
47 J = 50, 000 x²
x² = 47 /50,000
x² = 0.00094
x = 0.03066 m
Therefore,<u> x = 0.03066 m </u>