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3 years ago

9

A 22.0-kg child is riding a playground merrygo-round that is rotating at 40.0 rev/min. What centripetal force is exerted if he i

s 1.25 m from its center?

1 answer:

Tems11 [23]3 years ago

6 0

Answer:

F=480.491 N

Explanation:

Given that

mass ,m = 22 kg

Angular speed ω = 40 rev/min

$\omega=\dfrac{2\pi \times 40}{60}\ rad/s$

ω =4.18 rad/s

The radius r= 1.25 m

We know that centripetal force is given as

F=m ω² r

Now by putting the values in the above equation we get

$F=22\times 4.18^2\times 1.25\ N$

F=480.491 N

Therefore the centripetal force on the child will be 480.491 N.

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We make a graphic of this problem to define the angle.

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A uniform, solid, 2000.0 kgkg sphere has a radius of 5.00 mm. Find the gravitational force this sphere exerts on a 2.10 kgkg poi

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$0.0110284391534\ N$

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3 years ago

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