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zvonat [6]
3 years ago
9

A 22.0-kg child is riding a playground merrygo-round that is rotating at 40.0 rev/min. What centripetal force is exerted if he i

s 1.25 m from its center?
Physics
1 answer:
Tems11 [23]3 years ago
6 0

Answer:

F=480.491 N

Explanation:

Given that

mass ,m = 22 kg

Angular speed ω = 40 rev/min

\omega=\dfrac{2\pi \times 40}{60}\ rad/s

ω =4.18 rad/s

The radius  r= 1.25 m

We know that centripetal force is given as

F=m ω² r

Now by putting the values in the above equation we get

F=22\times 4.18^2\times 1.25\ N

F=480.491 N

Therefore the centripetal force on the child will be 480.491 N.

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The angle that the Sun’s rays strike a region of Earth determines the amount of heat transferred.
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4 years ago
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A 0.300 kg mass is attached to
scoundrel [369]

Answer:

0.144 J

Explanation:

From the question above,

Total elastic energy of the spring = Kinetic energy of the spring + potential energy of the spring

E' = E.k+Ep...................... Equation 1

Ek = E'-Ep......................... Equation 2

Where E' = total elastic energy, E.k = kinetic energy, E.p = potential  energy.

E'  = 1/2ke² = 1/2(26.6)(0.12²) = 0.19152 J.

Ep = 1/2ke² = 1/2(26.6)(0.06²)

Ep = 0.04788 J

Therefore,

Ek = 0.19152-0.04788

Ek = 0.144 J

8 0
3 years ago
What is the equivalent capacitance of the three capacitors in the figure (figure 1)?
vekshin1

The equivalent capacitance of the combination is  \dfrac{1}{C} = \dfrac{1}{C_1}+\dfrac{1}{C_2}  where C1 and C2 are the capacitance of both capacitors in series.

<h3>What is equivalent capacitor?</h3>

Let the capacitance of both capacitors be C1 and C2. For a series connected capacitors, same charge flows through the capacitors but different voltage flows through them.

Let Q be the amount of charge in each capacitors,

V be the voltage across each capacitors

C be the capacitance of the capacitor.

Using the formula Q = CV where V = Q/C... (1)

For the large capacitor with capacitance of the capacitor C1,

Q = C_1V_1;

V_1 = \dfrac{Q}{C_1}...(2)

where V_1 is the voltage across C_1,

For the small capacitor with capacitance of the capacitor C_2,

Q = C_2V_2;

V_2 = \dfrac{Q}{C_2} ... (3)

where V_2 is the voltage across C_2,

Total voltage V in the circuit will be;

V = V_1+V_2... (4)

Substituting equation 1, 2 and 3 in equation 4, we have;

\dfrac{Q}{C} = \dfrac{Q}{C_1} +\dfrac{ Q}{C_2}

\dfrac{Q}{C} = Q({\dfrac{1}{C_1}+\dfrac{1}{C_2})

Since change Q is the same for both capacitors since they are in series, they will cancel out to finally have;

\dfrac{1}{C} = ({\dfrac{1}{C_1}+\dfrac{1}{C_2})

This gives the equivalent capacitance of the combination.

To know more about equivalence capacitance follow

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7 0
2 years ago
A block of size 20m x 10 mx 5 m exerts a force of 30N. Calculate the
Orlov [11]

Answer:

We know that force applied per unit area is called pressure.

Pressure = Force/ Area

When force is constant than pressure is inversely proportional to area.

1- Calculating the area of three face:

A1 = 20m x 10 m =200 Square meter

A2 = 10 mx 5 m = 50 Square meter

A3 = 20m x 5 m = 100 Square meter

Therefore A1 is maximum and A2 is minimum.

2- Calculate pressure:

P = F/ A1 = 30 / 200 = 0.15 Nm⁻²  ( minimum pressure)

P = F / A2 = 30 / 50 = 0.6 Nm⁻²   ( maximum pressure)

Hence greater the area less will be the pressure and vice versa.

3 0
3 years ago
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