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Evgen [1.6K]
3 years ago
12

A spaceship far from all other objects uses its impulse power system to attain a speed of 104 m/s. The crew then shuts off the p

ower. According to Newton's first law, what will happen to the motion of the spaceship from then on? (Select all that apply.)
Physics
1 answer:
asambeis [7]3 years ago
4 0

Answer:

Velocity remains the same at 104 m/s

Explanation:

According to Newton's 1st law of motion, an object subjected to no force or net force equal 0 would maintain its velocity. In our case the crew shuts off the power, spaceship is in space and far from all other objects (so no gravity whatsoever) would have no force acting on it. Therefore its velocity would stay the same at 104 m/s

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Diana observed that the plants in her garden were not growing well due to poor soil conditions. She tested the soil and used the
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The appropriate answer is c. silty clay loam. This is the most likely soil that was present in the garden before sand was added to balance it. This type of soil contains an even mix of silt and clay. This type of soil does not drain well and tends to hold water. This would not be suitable for most garden variety plants. Adding sand to the soil ensures better drainage and removes moisture that would rot roots or create conditions for fungi to develop.
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3 years ago
Based on your answer,what idea comes in to your mind?​
valkas [14]

Answer:

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Explanation:

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3 years ago
After fixing a flat tire on a bicycle you give the wheel a spin. If its initial angular speed was 6.36 rad/s and it rotated 14.7
lesya692 [45]

To solve this problem we will apply the concepts related to the cinematic equations of angular motion. On these equations, angular acceleration is defined as the squared difference of angular velocity over twice the radial displacement. This is mathematically:

\alpha = \frac{\omega^2-\omega_0^2}{2\theta}

Our values are,

\text{Initial angular velocity} = \omega_0 =6.36 rad/s

\text{Final angular velocity} =  \omega =0

\text{Angular displacement} =  \theta = 14.7rev = 29.4\pi rad

Replacing,

\alpha = \frac{- 6.36^2}{29.4\pi}

\alpha = -0.43rad/s^2

Therefore the angular acceleration is -0.43rad/s^2

4 0
3 years ago
Bill and Ted are standing on a bridge 40 ft above a river. Bill drops a stone, while Ted decides to throw a stone downward at 10
Y_Kistochka [10]

Answer:

D) - 0.72 secs

Explanation:

Parameters given:

Height of bridge = 40ft = 12.19 m

Initial velocity of Bill's stone = 0m/s

Initial velocity of Ted's stone = 10m/s

We find the time it take Bill's stone to bit the river and the time it takes Ted's stone to hit the river. Then we find the time difference.

Using one of the equations of motion:

For Bill:

S = ut + ½gt²

Where g = 9.8 m/s

12.19 = 0 + ½*9.8*t²

t² = 12.19/4.9 = 2.49

t = 1.58 secs

For Ted:

S = uT + ½gT²

12.19 = 10*T + ½*9.8*T²

=> 4.9T² + 10T - 12.19 = 0

Using quadratic formula and retaining only the positive value, we get that:

T = 0.86 secs

Time difference between Bill's throw and Ted's throw is:

0.86 - 1.58 = - 0.72 secs

In reality, this means that Ted must throw his stone 0.72 secs before Bill throws his for both stones to land the same time.

6 0
4 years ago
Convert one mean solar day into second​
Naya [18.7K]

Answer:

86400 seconds

Explanation:

To convert a mean solar day to second :

Number of hours in a solar day = 24 hours

Number of minutes per hour = 60 minutes

Number of seconds per minute = 60 minutes

Hence, the number of seconds in a solar day is :

(Number of hours in a solar day * number of minutes in an hour * number of seconds in a minute)

(24 * 60 * 60) seconds = 86400 seconds

Hence, 1 mean solar day = 86400 seconds

3 0
3 years ago
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