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horsena [70]
2 years ago
12

Help! I need to do this quickly!!!

Physics
1 answer:
umka2103 [35]2 years ago
8 0
D is the answer. It is a firm statement.
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The sun emits energy by converting hydrogen into helium. what is this process called?
AleksAgata [21]
The answer is Nuclear Fusion. The sun emits energy by converting hydrogen into helium. Nuclear fusion does two things, it converts hydrogen into helium and it also converts mass to energy.
7 0
3 years ago
Raising the temperature of a gas will increase its pressure if the volume of the gas
ira [324]
That would be C .............
6 0
3 years ago
What is the force of a lead ball that starts with a momentum of 7 kg*m/s and end with a momentum of 22 kg*m/s over a time of 31
Gwar [14]

Answer:

F = 0.483 N

Explanation:

Initial momentum, P_i= 7\ kg-m/s

Final momentum, P_f= 22\ kg-m/s

Time, t = 31 s

We need to find the force of a lead ball. We can use here the impulse momentum theorem.

\text{Change in momentum}=F\times t

F is force

P_f-P_i=Ft\\\\F=\dfrac{P_f-P_i}{t}\\\\F=\dfrac{22-7}{31}\\\\F=0.483\ N

So, the force is 0.483 N.

6 0
3 years ago
An object is placed 18 cm in front of spherical mirror.if the image is formed at 4cm to the right of the mirror, calculate it's
ivolga24 [154]
1) Focal length

We can find the focal length of the mirror by using the mirror equation:
\frac{1}{f}= \frac{1}{d_o}+ \frac{1}{d_i} (1)
where 
f is the focal length
d_o is the distance of the object from the mirror
d_i is the distance of the image from the mirror

In this case, d_o = 18 cm, while d_i=-4 cm (the distance of the image should be taken as negative, because the image is to the right (behind) of the mirror, so it is virtual). If we use these data inside (1), we find the focal length of the mirror:
\frac{1}{f}= \frac{1}{18 cm}- \frac{1}{4 cm}=- \frac{7}{36 cm}
from which we find
f=- \frac{36}{7} cm=-5.1 cm

2) The mirror is convex: in fact, for the sign convention, a concave mirror has positive focal length while a convex mirror has negative focal length. In this case, the focal length is negative, so the mirror is convex.

3) The image is virtual, because it is behind the mirror and in fact we have taken its distance from the mirror as negative.

4) The radius of curvature of a mirror is twice its focal length, so for the mirror in our problem the radius of curvature is:
r=2f=2 \cdot 5.1 cm=10.2 cm
3 0
3 years ago
I'm looking for the answers for 4-6 and how to do them. I have some answers already but I'm very unsure of them. Thank you!
coldgirl [10]
Answer to 4: E

Answer to 6: D
7 0
3 years ago
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