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3 years ago

PLEASE HELP!! 20 POINTS!

2 answers:

7 0

It's something to do with the weathering process. Eg. At night it's really cold, and in the day it's really hot. Because the temperature keeps changing dramatically day in and day out, the sand dunes start to be sort of hacked or re-shaped, or even formed.

Free_Kalibri [48]3 years ago

4 0

Hi there!

This "phenomenon" happens because of erosion caused by wind and deposition. Wind picks up grains of sand and deposits it when the sand encounters an obstacle (in this case, a sand dune or the like). Because the sand is not held in place like soil, the dunes are constantly changing, allowing for varied shapes and sizes of the dunes every year Eli and his family visit.

I hope that helps you out! Have a great day! :)

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Nhóm axit nào tác dụng với mg tạo ra h2o

Yuri [45]

Answer:

yyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy

Explanation:

uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

4 0

2 years ago

Which of the following atoms is smallest: nitrogen, phosphorus, or arsenic?

snow_lady [41]

Answer:

arsenic

Explanation:

nitrogen=155pm

phosphorus=195pm

arsenic =between 38 μm and 25 mm

3 0

3 years ago

a ridged 2.40L sealed vessel contains He and C3H6 gases. The partial pressure of He is 1.4 atm and that of C3H6 is 1.7 atm, at 5

balandron [24]

Answer:

Partial pressure He → 0.96 atm

Partial pressure C₃H₆ → 1.18 atm

Explanation:

We apply the Charles Gay Lussac law, to solve this. Pressure varies directly proportional to absolute T°, when the volume keeps on constant.

P₁ / T₁ = P₂ / T₂

We convert the T° to absolute T°

55°C + 273 = 328K

-45°C + 273 = 228K

Total pressure = Sum of partial pressures

1.7 atm + 1.4 atm = 3.1 atm

When we apply the formula we would know the new total pressure

3.1 atm / 328K = P₂ / 228K

(3.1 atm / 328K) . 228K = 2.15 atm

As the moles has not been modified with the change of T°, we assume the mole fraction is still the same.

Mole fraction He = Partial pressure He / Total pressure

1.4 atm / 3.1 atm = 0.45

Mole fraction C₃H₆ = Partial pressure C₃H₆/ Total pressure

1.7 atm / 3.1 atm = 0.55

0.45 = Partial pressure He / 2.15 atm

Partial pressure = 0.45 . 2.15 atm → 0.96 atm

0.55 = Partial pressure C₃H₆ / 2.15 atm

Partial pressure = 0.55 . 2.15 atm → 1.18 atm

3 0

3 years ago

Help me pls and ty;)

creativ13 [48]

$\sf \red{Describing \: Sustainability}$

Which statement best describes how biodiversity supports the sustainability of an ecosystem.

biodiversity allows laws to be passed in order to protect species

biodiversity prevents habitats from being destroyed by people.

maintaining diversity allows species to use up the resources in an ecosystem .

maintaining diversity ensures that species to use up the resource in an ecosystem.

maintaining diversity ensures that species can continue to depend on one another

$\huge \sf{ {3}^{rd} \: option }$

4 0

3 years ago

A 12.0-liter sample of air at 25°C and 1.00 atm pressure was collected and dried. After drying, the volume of the sample was exa

zmey [24]

<u>Answer:</u> The mass percent of water in the original air sample is 4.16 %

<u>Explanation:</u>

We are given:

Volume of moist air = 12.0 L

Volume of dry air = 11.50 L

Volume of water lost = (12.0 - 11.50) L = 0.50 L

Here, the percent by mass ratio will be equal to the percent by volume ratio as the number of moles is directly related to the volume.

To calculate the volume percentage of water in the air, we use the equation:

$\text{Volume percent of water}=\frac{\text{Volume of water}}{\text{Volume of air}}\times 100$

Putting values in above equation, we get:

$\text{Volume percent of water}=\frac{0.50L}{12.00L}\times 100\\\\\text{Volume percent of water}=4.16\%$

Hence, the mass percent of water in the original air sample is 4.16 %

8 0

3 years ago