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irina1246 [14]
3 years ago
9

A large piece of iron was reacted with an acid. What would happen to the rate of the reaction had the large piece been finely di

vided into smaller pieces?
Chemistry
2 answers:
Anna007 [38]3 years ago
3 0
The reaction occurs in a similar way as magnesium does, but much less vigorous. Strong heating is required to make iron powder burn in oxygen. The reaction gives out a yellow showery sparks and produces a black solid. iron reacts with dilute hydrocloric acid to give iron chloride and hydrogen gas.
bekas [8.4K]3 years ago
3 0

For a reaction to occur there must be effective collision between the reactant molecules. When the iron or the reactant particles are finely divided that increases the surface area exposing more reactant particles on the surface and increase the rate of intermoleculer collision. The  greater effective collision between the reactant molecules the faster will the reaction occur.

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What region of the atom contains most of the atoms mass?
dimulka [17.4K]

Answer:

Nucleus

Explanation: it is the center of the atom, and contains protons and nuetrons

7 0
3 years ago
Read 2 more answers
Complete the table below by writing the symbols for the cation and anion that make up each ionic compound.
marysya [2.9K]

The ions are as follows;

  • As2O3 -  As^3+, O^2-
  • MnS - Mn^2+, S^2-
  • VCl3 - V^3+, Cl^-
  • NiF2 - Ni^2+,  F^-

<h3>What is a cation and an anion?</h3>

A cation is a positive ion while an anion is a negative ion. Ionic compounds are composed o cations and anions.

The anions and cations in the ionic compounds in the table are shown below;

  • As2O3 -  As^3+, O^2-
  • MnS - Mn^2+, S^2-
  • VCl3 - V^3+, Cl^-
  • NiF2 - Ni^2+,  F^-

Learn more about cations and anions:brainly.com/question/4933048

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6 0
2 years ago
What is the ph of a solution which is 0. 023 m in weak base and 0. 037 m in the conjugate weak acid ( a = 7. 1 × 10^−6)?
Rzqust [24]

The pH of a solution which is 0.023 m in weak base and 0 037 m in the conjugate weak acid whose Ka= 7.1 × 10⁻⁶ is 4.93.

pH determines the amount of hydrogen and hydroxide ions in a solution. It is the negative logarithm of hydrogen ion concentration.

Given,

Ka= 7.1 × 10⁻⁶

Weak base = 0.023M

Acid = 0.037M

Using base dissociation constant, Ka we can calculate pKa by:

pKa = -log [Ka]

pKa = -log [7.1 × 10⁻⁶]

pKa = 5.15

A weak base and its conjugate acid are present in equal proportions in buffer solution. Using the Henderson-Hasselbalch equation, we can find out the pH of a buffer solution that constitutes a weak base and its conjugate acid.

Using Henderson-Hasselbalch equation,

pH = pKa + log [Weak base / acid]

pH = 5.15 + log [0.023 / 0.037]

pH = 5.15 + log[0.6]

pH = 5.15 - 0.22

pH = 4.93

Therefore, the pH of the solution is 4.93.

Learn more about pH here, brainly.com/question/22390063

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5 0
2 years ago
Samples of f2 gas and xe gas are mixed in a container of fixed volume. the initial partial pressure of the f2 gas is 8.0 atmosph
anzhelika [568]
Answer is: XeF₄.
p₁ (F₂) = 8,0 atm.
p₁ (Xe) = 1,7 atm.
p₂ (F₂) = 4,6 atm.
p₂ (Xe) = 0 atm, all reacted.
p - partial pressure.
pressure of F₂ reacted = Δp (F₂) = 8.0 - 4.6 = 3.4 atm.
pressure of Xe reacted = Δp(Xe) = 1,7 - 0 = 1,7 atm.
Δp (F₂)  / Δp(Xe) = 3,4 atm / 1,7 atm = 2:1.
Reaction: 2F₂ + Xe → XeF₄ (xenon-tetrafluoride)
8 0
3 years ago
40.0% C, 6.72% H, 53.29%, O. Molar mass is 60 g/mol. Determine the empirical and molecular formula.
arsen [322]

Answer:

Molecular formula: C₂H₄O₂

Empirical formula: CH₂O

Explanation:

40 % C, 6.72 % H and 53.29 % O states the centesimal composition of the compound. These data means that in 100 g of compound we have x grams of a determined element.

We divide the mass by the molar mass of each:

40 g / 12 g/mol = 3.33 moles of C

6.72 g / 1 g/mol = 6.72 moles of H

53.29 g / 16 g/mol = 3.33 moles of O

We can determine rules of three to get, the molecular formula.

In 100 g of compound we have 3.33 moles of C, 6.72 moles of H and 3.33 moles of O; therefore in 60 g (1 mol) we must have

- (60 . 3.33) / 100 = 2 moles of C

- (60 . 6.72) / 100 = 4 moles of H

- (60 . 3.33) / 100 = 2 moles of O

Molecular formula is C₂H₄O₂

Empirical formula has the lowest suscripts; we divide by two, so the empirical formula is CH₂O

3 0
3 years ago
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