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makvit [3.9K]
3 years ago
13

Match the words to the definitions below.

Chemistry
1 answer:
puteri [66]3 years ago
5 0

Answer:

Explanation:

1. Turns litmus paper blue, taste bitter, donate OH- ions, feel slippery, 8-14 on pH scale.

BASE

BASE: A base is a substance that reacts with water to yield excess hydroxide ions.

Some of its characteristics are:

>It has a bitter taste

>Their aqeuos solutions have a soapy feel

>They have a PH greater than 7

>They turn red litmus paper blue

>They are electrolytes

2. The amount of ions per an amount of solvent. Ex: 10g salt/100g water

CONCENTRATION

Concentration is the amount of solute that can be found in a solution.

3. A lab procedure to deliver a measured volume of solution, generally measured in ml.

TITRATION

Titration is a laboratory procedure that is used to determine the amount of solution that is needed to drive a reaction to completion. It involves adding a solution to a known volume of another solution.

4. A substance or solution that resists changes in pH by stabilizing hydrogen ion concentration.

BUFFER

A buffer is solution that is made up of weak acids and their salts or weak bases and their salts. Such solutions are able to resist changes in PH

5. Turns litmus paper red, taste sour, donate H+, corrode metals, 0-6 on pH scale.

ACID

An acid is a proton donor, hydrogen ions.

Characteristics:

>Acids turns blue litmus paper red, they have sour taste and easily corrodes metals.

>They have a PH value between 0-6 on the scale.

>They are generally electrolytes

6. Logarithmic scale to indicate the amount of hydrogen ions in solution.

PH SCALE

A PH scale is a logarithmic scale that runs from 1-14 and is used to indicate the amount of hydrogen ions in a solution.

7. A chemical (dye created from lichens) that changes color in response to changes in pH.

LITMUS PAPER

Litmus paper is made of dyes created from lichen and it changes its color as PH changes. Acids turns blue litmus paper red while bases changes the color of litmus to blue from red. Litmus test is a popular test for solutions.

8. Acids and bases are added proportionally and result in a chemical reaction that causes the pH of a solution to reach pH 7.

NEUTRALIZATION

Neutralization is the reaction of acids and bases to produce salts and water. The endpoint of neutralization reaction signifies the point at which equal number of bases neutralizes an acid. The PH is 7 at this point.

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A sample of neon has a volume of 40.81 m3 at 23.5C. At what temperature, in Kelvins, would the gas occupy 50.00 cubic meters? As
mezya [45]

At  \fbox{\begin \\363 K \end{minispace}}  temperature, a sample of neon gas will occupy 50.00 \text{ m}^{3} volume.

Further Explanation:

The given problem is based on the concept of Charles’ law. Charles’ law states that “at constant pressure and fixed mass the volume occupied an ideal gas is directly proportional to the Kelvin temperature.”

Mathematically the law can be expressed as,

\fbox{ \begin \\ V \propto T \end{minispace}}

Or,

\frac{V}{T}=k

Here, <em>V</em> is the volume of the gas, <em>T</em> is Kelvin temperature, and <em>k</em> is proportionality constant.

Given information:

The initial volume of neon gas is 40.81 \text{ m}^{3} .

The final volume of neon gas is  50.00 \text{ m}^{3}.

The initial temperature value is 23.5 \text{ } ^{\circ} \text{C} .

To calculate:

The final temperature

Given Condition:

  • The pressure is constant.
  • Mass of gas is fixed.

Solution:

Step 1: Modify the mathematical expression for Charles’ law for two different temperature and volume values as follows:

\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}

Here,

  • V_{1}is the initial volume of the gas.
  • V_{2} is the final volume of the gas.
  • T_{1} is the initial temperature of the gas.
  • T_{2} is the final temperature of the gas.

Step 2: Rearrange equation (2) for .

\fbox {\begin \\T_{2}=\frac{(V_{2}) \times (T_{1})}{V_{1}}\\\end{minispace}}                                                                  …… (2)

Step 3: Convert the given temperature  from degree Celsius to Kelvin.

The conversion factor to convert degree Celsius to Kelvin is,

T(\text{K}) = T(^{\circ}\text{C}) + 273.15                                      …… (3)

Substitute 23.5\text{ }^{\circ} \text{C} for T(^{\circ}\text{C})  in equation (3) to convert temperature from degree Celsius to Kelvin.

T(\text{K}) = 23.5 \text{ } ^{\circ} \text{C} + 273.15\\T(\text{K})= 296.65 \text{ K}

Step 4: Substitute 40.81 \text{ m}^{3}  for V_{1} ,  50.00 \text{ m}^{3} for V_{2}  and  296.65 \text{ K} for T_{1}  in equation (2) and calculate the value of T_{2} .

T_{2}=\frac{(50.00 \text{ m}^{3}) \times (296.65 \text{ K})}{40.81 \text{ m}^{3}}\\T_{2}=363.45 \text{ K}\\T_{2} \approx 363 \text{ K}

Important note:

  • The temperature must be in Kelvin.
  • The condition of fixed mass and fixed pressure must be fulfilled in order to apply Charles’ law.

Learn More:

1. Gas laws brainly.com/question/1403211

2. Application of Charles’ law brainly.com/question/7434588

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: States of matter

Keywords: neon, volume, occupies, temperature, Kelvin, degree Celsius, Charle’s law, constant pressure, fixed mass, 40.81 m^3 , 50.00 m^3 , 23.5 degree C , celsius , 363 K , sates of matter, initial volume, final volume, initial temperature, final temperature, V1 , V2 , T1 , T2 .

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Explanation:

pOH = - log [OH⁻]

pOH = - log (9.0 x 10⁻⁷)

pOH = 6.0457

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Answer:

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