Describe the rise and fall of a thrown basketball by using the concepts o kinetic energy and potential energy

2 answers:

7 0

In first moment, ball has max kinetic energy and it gravitational potential is lowest. On the maximum height, kinetic energy is lowest and the gravitational is lowest. Moment before ball hits ground its kinetic energy is highest and gravitational potential is lowest.

denpristay [2]3 years ago

6 0

Explanation:

The kinetic energy is due to the motion of the object.

The potential energy is due to the position of the object.

When a basketball is thrown upward then the kinetic energy decreases and the potential energy will be maximum when it will reach its maximum height.

When it starts falling then potential energy starts decreases due to the decrease in the height and the kinetic energy starts increases.

You might be interested in

What is Newton’s first law

amid [387]

Newton's First Law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force.

6 0

3 years ago

Read 2 more answers

Which balloon would fall faster, water filled or murcury filled?

bazaltina [42]

A mercury filled balloon would fall faster then water. Mercury is heavier.

7 0

3 years ago

10. In Freudian theory, which one of the following is an example of a Thanatos instinct, which includes aggression, trauma, and

Lelechka [254]

D substance abuse :) hope this helps

8 0

2 years ago

In making the determination that bullets, shells, or cartridge cases were fired from a specific weapon, the criminalist would us

ss7ja [257]

Answer:

Comparison Microscope

Explanation:

The Comparison Microscope allows for comparison between two objects or samples by placing them side by side.

It is primarily used in criminology for ballistics which makes it ideal to find out if bullets, shells, or cartridge cases were fired from a specific weapon.

7 0

3 years ago

Un ladrillo se le imparte una velocidad inicial de 6m/s en su trayectoria hacia abajo. ¿cual sera su velocidad final despues de

marshall27 [118]

Saludos!

Respuesta:

28,64 m/s.

Explicación:

Datos:

Altura o distancia recorrida: 40 m
Vo: 6 m/s
Aceleración de la gravedad: 9,81 m/s²

El ejercicio puede ser resuelto facilmente utilizando la siguiente formula, sin embargo es posible realizarlo utilizando formulas diferentes.

Entonces tenemos que:

$Vf ^{2} -Vo ^{2} =2 x g x h$

Es importante saber que al estar lanzando el ladrillo hacia abajo, el sentido del movimiento sigue el sentido de la gravedad, es decir es necesario que tomes el valor de la gravedad como positivo (+) y no negativo (-) como normalmente se usa.

Sustituyendo tenemos que:

$Vf x^{2} =(6 m/s) ^{2} +(2)x(9,81 m/s ^{2})x(40m) \\ Vf ^{2} =820,8 m^{2} /s ^{2} \\ \sqrt{Vf ^{2} } = \sqrt{820,8m^{2}/s ^{2} } \\ Vf=28,64 m/s$

Que tengas un buen día!

6 0

3 years ago