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WINSTONCH [101]
4 years ago
5

3. A cat is moving at 18 m/s when it accelerates at 4 m/s2 for 2 seconds. What is

Physics
1 answer:
salantis [7]4 years ago
4 0

Answer:

v=u+at

v=8+(4x2)

v=16m\s2

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Help me pls its important
Shkiper50 [21]
I believe B, but don’t take my word
6 0
2 years ago
A rocket sled for testing equipment under large accelerations starts at rest and accelerates according to the expression a = (3.
mash [69]

Answer:

9.6 m

Explanation:

This is a  case of motion under variable acceleration . So no law of motion formula will be applicable here. We shall have to integrate the given equation .

a = 3.6 t + 5.6

d²x / dt² = 3.6 t + 5.6

Integrating on both sides

dx /dt = 3.6 t² / 2 + 5.6 t + c

where c is a constant.

dx /dt = 1.8  t²  + 5.6 t + c

when t = 0 , velocity dx /dt is zero

Putting these values in the equation above

0 = 0 +0 + c

c = 0

dx /dt = 1.8  t²  + 5.6 t

Again integrating on both sides

x = 1.8 t³ / 3 + 5.6 x t² /2 + c₁

x = 0.6 t³  + 2.8  t²  + c₁

when t =0,  x = 0

c₁ = 0

x = 0.6 t³  + 2.8  t²  

when t = 1.6

x = .6 x 1.6³ + 2.8 x 1.6²

= 2.4576 + 7.168

= 9.6256

9.6 m

5 0
3 years ago
A particle of mass m=5.00 kilograms is at rest at t=0.00 seconds. a varying force f(t)=6.00t2−4.00t+3.00 is acting on the partic
olga_2 [115]

Answer:

The speed v of the particle at t=5.00 seconds = 43 m/s

Explanation:

Given :

mass m = 5.00 kg

force f(t) = 6.00t2−4.00t+3.00 N

time t between t=0.00 seconds and t=5.00 seconds

From mathematical expression of Newton's second law;

Force = mass (m) x acceleration (a)

F = ma              

a = \frac{F}{m}      ...... (1)

acceleration (a) = \frac{dv}{dt}   ......(2)

substituting (2) into (1)

Hence, F = \frac{mdv}{dt}

\frac{dv}{dt} = \frac{F}{m}

dv = \frac{F}{m} dt

dv = \frac{1}{m}Fdt

Integrating both sides

\int\limits {} \, dv = \frac{1}{m} \int\limits {F(t)} \, dt

The force is acting on the particle between t=0.00 seconds and t=5.00 seconds;

v = \frac{1}{m} \int\limits^5_0 {F(t)} \, dt     ......(3)

Substituting the mass (m) =5.00 kg of the particle, equation of the varying force f(t)=6.00t2−4.00t+3.00 and calculating speed at t = 5.00seconds into (3):

v = \frac{1}{5} \int\limits^5_0 {(6t^{2} - 4t + 3)} \, dt

v = \frac{1}{5} |\frac{6t^{3} }{3} - \frac{4t^{2} }{2} + 3t |^{5}_{0}

v = \frac{1}{5} |(\frac{6(5)^{3} }{3} - \frac{4(5)^{2} }{2} + 3(5)) - 0|

v = \frac{1}{5} |\frac{6(125)}{3} - \frac{4(25)}{2} + 15 |

v = \frac{1}{5} |\frac{750}{3} - \frac{100}{2} + 15 |

v = \frac{1}{5} | 250 - 50 + 15 |

v = \frac{215}{5}

v = 43 meters per second

The speed v of the particle at t=5.00 seconds = 43 m/s

6 0
3 years ago
One component of a metal sculpture consists of a solid cube with an edge of length 24.5 cm . The alloy used to make the cube has
boyakko [2]

Answer:

118kg

Explanation:

answered

Given

density of the cube= 8050 kg/m3 .

length of the sizes of the cube=24.5 cm

We can convert the length to cm for unit consistency.

It's length =24.5 cm =0.245m

✓ the length of sizes of the cube is the same, then the volume can be calculated as

Volume= L^3

= (0.245m)^3

=0.01470625 m^3

✓ but we know that

Density = mass/ volume

Then,

Mass= (Volume × density)

= (0.01470625)(8050)

= 118 kg

Hence, the mass of the cube is 118 kg

8 0
3 years ago
Where does internal radiation come from?
pantera1 [17]

☁️ Answer ☁️

Internal radiation exposure hazards result from radioactive material that gets inside the body when you breathe it

Hope it helps.

Have a nice day hyung/noona!~  ̄▽ ̄❤️

5 0
3 years ago
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