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3 years ago

10. Waves bounce back when they meet a surface. This is called...

Chemistry

1 answer:

bogdanovich [222]3 years ago

7 0

When waves bounce back after meeting a surface, it is called Reflection.

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A compound is analyzed and found to be 50% sulfur and 50% oxygen. If the total amount of the sulfur oxide is 12.5 g, how many gr

il63 [147K]

Answer:

25.0g is the mass of sulfur

Explanation:

The sulfur and the oxygen are 50:50. That means there is 1 mole of S per mole of O.

To solve this question we need to convert the mass of O to moles, as moles of O = Moles of S, we can find the moles of S and its mass:

<em>Moles O = Moles S:</em>

12.5g O * (1mol / 16g) = 0.781 moles

0.781 moles * (32g / mol) =

<h3>25.0g is the mass of sulfur</h3>

7 0

2 years ago

How does increasing the concentration of a nonvolatile solute in water affect the following properties:Vapor pressure: Decreases

PIT_PIT [208]

Answer: Osmotic pressure : increases

Explanation:

Osmotic pressure is the minimum pressure which is applied to a solution to prevent the flow of solvent across a semipermeable membrane

$\pi =CRT$

$\pi$ = osmotic pressure

C= concentration in Molarity (number of moles of solute dissolved per liter of the solution)

R= solution constant

T= temperature

Thus as osmotic pressure is directly proportional top concentration, osmotic pressure will increase on increasing the concentration of a nonvolatile solute in water.

8 0

2 years ago

What do you think is the primary reason why the Unionid mussel population declined whenever there is a dramatic increase in the

sertanlavr [38]

Answer:

When the Zebra arrived they ate all the food so the Unionid mussels declined as they died from the lack of food. Causing the Zebra Zebra numbers to increase and Unionid numbers to decline.

6 0

2 years ago

How many grarns would 3 moles of carbon dioxide (CO2) weigh? (round to the

BigorU [14]

Mass of CO₂ = 132 g

<h3>Further explanation </h3>

A mole is a number of particles(atoms, molecules, ions) in a substance

This refers to the atomic total of the 12 gr C-12 which is equal to 6.02.10²³, so 1 mole = 6.02.10²³ particles

Can be formulated :

N = n x No

N = number of particles

n = mol

No = 6.02.10²³ = Avogadro's number

mole also can be formulated :

$\tt n=\dfrac{mass}{MW}$

moles of CO₂ = 3

mass of CO₂(MW=44.01 g/mol) :

$\tt mass=mol\times MW\\\\mass=3\times 44.01\\\\mass=132.03~g\approx 132~g$

6 0

2 years ago

Consider the following reaction where Kc = 1.80×10-2 at 698 K:2 HI (g) H2 (g) + I2 (g)A reaction mixture was found to contain 0.

Iteru [2.4K]

Answer:

Answer for the given statements: (1) T , (2) F , (3) T , (4) F , (5) F

Explanation:

At the given interval, concentration of HI = $\frac{0.304}{1}M=0.304M$

Concentration of $H_{2}$ = $\frac{5.07\times 10^{-2}}{1}M=5.07\times 10^{-2}M$

Concentration of $I_{2}$ = $\frac{4.57\times 10^{-2}}{1}M=4.57\times 10^{-2}M$

Reaction quotient, $Q_{c}$ , for this reaction = $\frac{[H_{2}][I_{2}]}{[HI]^{2}}$

species inside third bracket represents concentrations at the given interval.

So, $Q_{c}=\frac{(5.07\times 10^{-2})\times (4.57\times 10^{-2})}{(0.304)^{2}}=2.51\times 10^{-2}$

So, the reaction is not at equilibrium.

As $Q_{c}> K_{c}$ therefore reaction must run in reverse direction to reduce $Q_{c}$ and make it equal to $K_{c}$ . That means HI(g) must be produced and $H_{2}$ must be consumed.

3 0

2 years ago