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stepan [7]
3 years ago
11

Aqueous solutions of a compound did not form precipitates with cl-, br-, i-, so42-, co32-, po43-, oh-, or s2-. this highly water

-soluble compound produced the foul-smelling gas h2s when the solution was acidified. this compound is ________.
Chemistry
1 answer:
sergij07 [2.7K]3 years ago
3 0
<h3><u>Answer;</u></h3>

(NH4)2S

<h3><u>Explanation;</u></h3>
  • Ammonium sulphide, (NH4)2S, is an unstable compound, and in aqueous solution it exists as ammonia (NH4OH) and ammonium hydrosulphide, NH4HS.
  • it is a highly water-soluble compound and produces the foul-smelling gas h2s when the solution is acidified.
  • The anions; cl-, br-, i-, so42-, co32-, po43-, oh-, or s2- are not precipitated by (NH4)2S, but are precipitated by salts such as barium and silver nitrate.
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4 years ago
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Hello this is my 3 attempt, please someone answer this i'm begging you.
denis23 [38]

Answer:

Explanation:

No worries, I got you :)

So for the first question, you need to use PV=nRT to find the n, or in other words, the number of moles. Then, you can find the molar mass since you know the grams and the moles

110 kPa / 101.3 = 1.085 atm (I converted it to atm so I can use the .08206 L atm/ k mol  for the rate)

550 ml / 1000 = .550 L (I converted mL to L in order to use the .08206 L atm/ k mol for the Rate)

28.5 c + 273 = 301.5 K (I converted C to K in order to use the .08206 L atm/ k mol for the Rate)

PV=nRT

(1.085) (.550 L) = n (0.08206) (301.5)

Divide the (0.08206) (301.5) to get n alone:

(1.085) (.550 L) / (0.08206) (301.5) = n

When I divided, I got n= .02412 moles, and since we have 1.88g , we divide the 1.88 by .02412 to get the molar mass (grams/mole)

77.94 g/mole is the molar mass

we know that there are 3 H's in the compound, so we do 3(1.008) and subtract 77.94 by what you get.

3 x 1.008 = 3.024 -----> 77.94-3.024 = 74.9

Now we look at the periodic table and try to find an element that has a molar mass of 74.9

Arsenic (As) has a molar mass of 74.922, which is close enough. Plus, Arsenic has a charge of 3, so it fits with the 3 hydrogens.

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3 years ago
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Answer:

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