Answer:
In full volume it contain 0.12 moles.
Explanation:
Given data:
Total volume= Vt = 2.9 L
Decreased volume= Vd = 1.2 L
Number of moles of air present in decreased volume= n = 0.049 mol
Number of moles of air in total volume= n = ?
Solution:
Formula:
Vt/ Vd = n (in total volume) /n ( decreased volume)
2.9 L / 1.2 L = X / 0.049 mol
2.42 = X / 0.049 mol
X = 2.42 × 0.049
X = 0.12 mol
Answer: 1.9 moles SO₂
Explanation:
1) The chemical formula SO₂ shows that for every mol of SO₂ there are 1 mol of S and two moles of O.
2) Then you can state the proportion between the number of moles of SO₂ and O to find how many moles of SO₂:contains 3.8 moles of O.
1 mol SO₂ x
-------------------- = --------------------------
2 moles O 3.8 moles O
3) Now, you can clear x:
x = 3.8 moles O × 1 mol SO₂ / 2 moles O.
x = 1.9 moles SO₂.
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