To prevent drainage of the transmission fluid from the converter when the
1 answer:
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Answer:
A) W' = 15680 KW
B) W' = 17113.87 KW
Explanation:
We are given;
Temperature at state 1; T1 = 290 K
Temperature at state 3; T3 = 1100 K
Rate of heat transfer; Q_in = 35000 kJ/s = 35000 Kw
Pressure of air into compressor; P_c = 95 kPa
Pressure of air into turbine; P_t = 760 kPa
A) The power assuming constant specific heats at room temperature is gotten from;
W' = [1 - ((T4 - T1)/(T3 - T2))] × Q_in
Now, we don't have T4 and T2 but they can be gotten from;
T4 = [T3 × (r_p)^((1 - k)/k)]
T2 = [T1 × (r_p)^((k - 1)/k)]
r_p = P_t/P_c
r_p = 760/95
r_p = 8
Also,k which is specific heat capacity of air has a constant value of 1.4
Thus;
Plugging in the relevant values, we have;
T4 = [(1100 × (8^((1 - 1.4)/1.4)]
T4 = 607.25 K
T2 = [290 × (8^((1.4 - 1)/1.4)]
T2 = 525.32 K
Thus;
W' = [1 - ((607.25 - 290)/(1100 - 525.32))] × 35000
W' = 0.448 × 35000
W' = 15680 KW
B) The power accounting for the variation of specific heats with temperature is given by;
W' = [1 - ((h4 - h1)/(h3 - h2))] × Q_in
From the table attached, we have the following;
At temperature of 607.25 K and by interpolation; h4 = 614.64 KJ/K
At T3 = 1100 K, h3 = 1161.07 KJ/K
At T1 = 290 K, h1 = 290.16 KJ/K
At T2 = 525.32 K, and by interpolation, h2 = 526.12 KJ/K
Thus;
W' = [1 - ((614.64 - 290.16)/(1161.07 - 526.12))] × 35000
W' = 17113.87 KW
Answer:
the minimum width is b= 0.1414m = 141mm
Explanation:
]given,
L= 4.25
w₀ = 5.5kN/m,
allowable bending stress = 7MPa
allowable shear stress = 875kPa
h/b = 0.67
b = ?
for a linearly distributed load, with maximum load intensity, w₀ of 5.5kN/m,
the maximum moment, M exerted by the timber is =
given h/b = 0.67, i.e h=0.67b
allowable bending stress = = 7000kPa
7000 = (6*6.37)/ (b *(0.67b)² ) = 38.21/0.449b³
3080b³=38.21
b³ = 38.21/3080 = 0.0124
b = 0.232m
h=0.67b = 0.67* 0.232 = 0.155m
for allowable shear stress = (3V)/(2bh)
875 = (3V)/(2bh) = (3x 7.79)/(2xbx0.67b)
875 = 23.375/1.34b²
1172.5 b²= 23.375
b² =0.0199
b= 0.1414m
h=0.67b = 0.67* 0.1414 = 0.095m
the minimum width is b= 0.1414m = 141mm