Explanation:
The federal highway administration reports nearly 800 work zone fatalities per year.
The speed of the car A is 6.05 m/s and the speed of the car B just after the collision 7.65 m/s.
Ma=15 mg , Mb=25mg
Vai=5 m/s vbi=7 m/s
We know coeffecient of restitution
e=|Vaf-Vbf/Vai-Cbi|
0.8=|Vaf-Vbf/5-7|
Vaf-Vbf=1.6
MaVa+mbVb=MaVaf+MbVbf
15*5*25*7=15Vaf+25Vbf
3Vaf+5Vbf=50
sovleving eq 1 and 2
Vbf =6.05 m/s
Vaf=7.65 m/s
The speed of a change in an object's location in any direction. The distance traveled divided by the time required to travel that distance is the definition of speed.Due to its lack of magnitude and merely having a direction, speed is a scalar number. The average speed of an object can be determined if you know the distance traveled and the time it took. Distance times speed is how speed is calculated.
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The rotor is situated inside the stator and is mounted on the AC motor's shaft. It is the rotating part of the AC motor. And while we know this, the major function of the rotor and the stator is helping the motor shaft rotate.
Answer:
Iin(t) =1.3 × (-0.8/1.56) e^-t/1.56 A
Explanation:
In physics, the determination of the term " natural response" simply means that we want to know what happens in a circuit when the value of t = 0, that is to say after the circuit has been disconnected. Hence, the value of the voltage and the current can then be determined or Calculated;
For the the natural response of i in(t) we will be using the formula below;
I(t) = Vo × t/ R = Vo/R × e^-t/h.
Where h = 1/RC = time constant.
For t= 0^- = 0.8 × 1= 0.8 V.
1/Ctotal = 1/ 2 + 1/3 = 6/5
For t = 0^+;
h =( 0.8 + 0.5) × 6/5 = 1.56 seconds.
Hence, we will have;
Vin(t) = 0.8 × e^-t/1.56.
Iin(t) =1.3 × (-0.8/1.56) e^-t/1.56
Answer:
676 ft
Explanation:
Minimum sight distance, d_min
d_min = 1.47 * v_max * t_total where v_max is maximum velocity in mi/h, t_total is total time
v_max is given as 50 mi/h
t_total is sum of time for right-turn and adjustment time=8.5+0.7=9.2 seconds
Substituting these figures we obtain d_min=1.47*50*9.2=676.2 ft
For practical purposes, this distance is taken as 676 ft
