Question

What are the magnitudes of (a) the angular velocity, (b) the radial acceleration, and (c) the tangential acceleration of a spaceship taking a circular turn of radius 3220 km at a speed of 29 000 km/h?

Answer 1

Answer:

Part a)

Angular speed is given as

$\omega = 2.50 \times 10^{-3} rad/s$

Part b)

Radial acceleration of the spaceship is given as

$a_c = 20.15 m/s^2$

Part c)

Since we know that it is moving with constant speed

so tangential acceleration must be ZERO

Explanation:

As we know that tangential speed of the spaceship is given as

$v = 29000 km/h$

$v = 8055.55 m/s$

a)

Angular speed is given as

$\omega = \frac{v}{R}$

$\omega = \frac{8055.55}{3220\times 10^3}$

$\omega = 2.50 \times 10^{-3} rad/s$

Part b)

Radial acceleration of the spaceship is given as

$a_c = \omega^2 R$

$a_c = (2.50 \times 10^{-3})^2(3220\times 10^3)$

$a_c = 20.15 m/s^2$

Part c)

Since we know that it is moving with constant speed

so tangential acceleration must be ZERO