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vodka [1.7K]
3 years ago
10

How many grams of nitrogen are needed to produce 812 grams of ammonia?

Chemistry
1 answer:
viva [34]3 years ago
8 0
Is this multi choice or no?
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Hydrogen cyanide, HCN, is prepared from ammonia, air, and natural gas (CH₄), by the following process:
kykrilka [37]

Answer:

6.75 g of HCN can be produced by the reaction

Explanation:

Complete reaction is:

2NH₃ (g) + 3O₂ (g) + 2CH₄ (g) → 2HCN (g) + 6H₂O (g)

Let's determine the moles of each reactant:

11.5 g . 1mol / 17g = 0.676 moles of ammonia

12 g . 1 mol / 32g = 0.375 moles of oxygen

10.5 g . 1mol/ 16 g =  0.656 moles of methane

Now is all about rules of three:

2 moles of ammonia reacts with 3 moles of O₂ and 2 moles of methane

0.676 moles of NH₃ may react with:

(0.676 . 3) /2 = 1.014 moles of O₂

(0.676 . 2) / 2 = 0.676 moles of methane

Both can be the limiting reactant.

3 moles of O₂ react with 2 moles of NH₃ and 2 moles of methane

0.375 moles of O₂ will react with:

(0.375 .2) / 3  = 0.375 moles

The same amount for methane, 0.375 moles

2 moles of CH₄ reacts with 3 moles of O₂ and 2 moles of NH₃

0.656 moles of methane would react with 0.656 moles of NH₃

(0.656 . 3 ) /2 = 0.437 moles of O₂   I do not have enough O₂

Oxygen is the limiting reactant → We can work with the reaction now.

Ratio is 3:2. 3 moles of oxygen produce 2 moles of cyanide

0.375 moles of O₂ may produce (0.375 .2 ) / 3 = 0.250 moles

If we convert the moles to mass → 0.250 mol . 27 g / 1mol = 6.75 g

4 0
3 years ago
Which of the following blackbody curves is representative of stars like our Sun?
Xelga [282]

Answer:

its letter b

Explanation:

it represents the spectrum of stars

3 0
3 years ago
What is the compound of KCN called
mash [69]
Potassium Cyanide, is the compound of KCN.
3 0
3 years ago
Which order system shows the levels of organization from largest to smallest
Yanka [14]

Answer:

the answer is organism tissue organ system organ cell

7 0
3 years ago
How many molecules are present in 1 teaspoon of sucrose if its mass is 4.10g? show your work
frozen [14]
4.10 g C12H22O11 * ( 1 mol / 342.2965 g ) * ( 6.022x10^23 / 1 mol ) = <span>7.2107077x10^21 molecules = 7.21x10^21 molecules

Convert grams to moles using the molar mass ( g/mol ).

Use Avogadro's constant ( 6.022x10^23 ) to get the quantity of molecules from the amount of moles.

Revise answer to have the correct number of significant figures ( the smallest amount of digits in any number in the problem is the amount of significant figures your answer should have ).</span>
7 0
3 years ago
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