Answer:
The wavelength of light is 68 nm.
Explanation:
Given data:
Binding energy of electron = 176 × 10³ Kj/ mol or (1.76× 10⁶ j/mol)
Wavelength of light require to remove the electron = ?
Solution:
E = hc / λ
h = planck constant (6.63×10⁻³⁴ J/s)
c = speed of light = (3×10⁸ m/s)
The energy require per electron is
1.76 × 10⁶ j / 6.02× 10²³ = 2.92 × 10⁻¹⁸ J
Now we will put the values in formula,
E = hc / λ
λ = hc / E
λ = 6.63×10⁻³⁴ m².kg.s⁻¹ . 3×10⁸ m/s / 2.92 × 10⁻¹⁸ J
λ = 19.89×10⁻²⁶ m /2.92 × 10⁻¹⁸ (m².kg.s⁻² = J)
λ = 6.8 ×10⁻⁸ m
λ = 6.8 ×10⁻⁸ × 10⁹
λ = 68 nm
Answer:
[Ne] 3s² 3p²
Explanation:
Silicon atoms have 14 electrons. The ground state electron configuration of ground state gaseous neutral silicon is 1s²2s²2p⁶3s²3p².
Using noble gas shorthand, the electronic configuration is reduced to;
[Ne] 3s² 3p². Ne s the nearest noble gas to silicon, Ne contains 8 electrons, this means there's still 4 more electrons to fill. The s orrbital can only hold 2, hence the reaing two is transferred to the p orbital.
Answer:
43.89 min
Explanation:
Given that:-
The speed of light = 
The distance = 
The conversion of distance in km to distance into m is shown below as:-
1 km = 1000 m
So,
Distance = 
The relation between speed distance and time is shown below as:-
Thus,
Time = 2633.33 seconds
Also, 1 s = 1/60 min
So,
Time=
Carbon dioxide (CO2)
in the process of respiration, oxygen and glucose react to form carbon dioxide and water.
<span>Begin by classifying which energy level, and indirectly principal quantum number, n, resembles to the N shell.
no. of orbitals =n2
In your case, the fourth energy level will contain
n=4⇒no. of orbitals= 4^2=16
The number of subshells is given by the principal quantum number.
no. of subshells=n
In your case, the fourth energy level will have
no. of subshells = 4 this is the answer
to check:
the fourth energy shell will can hold a thoroughgoing of no. of electrons=2⋅42=32 e−</span>
