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Hatshy [7]
2 years ago
13

A convex refracting surface has a radius of 12 cm. Light is incident in air (n = 1) and refracted into a medium with an index of

refraction of 1.5. Light incident parallel to the central axis is focused at a point _____________
Physics
1 answer:
OLga [1]2 years ago
6 0

Answer:

<h2>36cm from the surface</h2>

Explanation:

Equation of refraction of a lens is expression according to the formula given below;

\dfrac{n_2}{v} = \dfrac{n_1}{u}=  \dfrac{n_2-n_1}{R}

R is the radius of curvature of the convex refracting surface = 12cm

v is the image distance from the refracting surface

u  is the object distance from the refracting surface

n₁ and n₂ are the refractive indices of air and the medium respectively

Given parameters

R = 12 cm

u = \infty (since light incident is parallel to the axis)

n₁  = 1

n₂  = 1.5

Required

<em>focus point of the light that is incident and parallel to the central axis (v)</em>

<em />

Substituting this values into the given formula we will have;

\dfrac{1.5}{v} - \dfrac{1}{\infty}=  \dfrac{1.5-1}{12}\\\\\dfrac{1.5}{v} -0=  \dfrac{0.5}{12}\\\\\dfrac{1.5}{v}=  \dfrac{0.5}{12}\\\\

Cross multiply

1.5*12 = 0.5*v\\ \\18 = 0.5v\\\\v = \frac{18}{0.5}\\ \\v = 36cm

Hence  Light incident parallel to the central axis is focused at a point 36cm from the surface

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