Question

A truck carrying a 65.4-kg crate accelerates from rest to [07]____________________ km/hr on a flat horizontal surface in 15.2 seconds. The acceleration was not constant. How much work (J) was done on the crate by the truck?

Answer 1

Answer:

The work done on the crate by the truck is 9472.54 J.

Explanation:

Given that,

Mass of the truck, m = 65.4 kg

Initially, the object is at rest, u = 0

Final speed of the truck, v = 61.3 km /h = 17.02 m/s

m/s

Time, t = 15.2 s

We need to find the work done on the crate by the truck. The work done is equal to the change in kinetic energy of the truck as :

$W=\Delta K$

$W=K_f-K_i$

$W=K_f-0$

$W=\dfrac{1}{2}mv^2$

$W=\dfrac{1}{2}\times 65.4\times (17.02)^2$

$W=9472.54\ J$

So, the work done on the crate by the truck is 9472.54 J. Hence, this is the required solution.