Answer:
The answer is = 5.81*10-7 N/m
Explanation:
From the above question, the first step to take is to find the magnitude of the net force per unit length acting on wire 3 due to the currents in the other wires
Solution
Given
The magnitude of the net force per unit length moving on wire 3 due to the currents in the other wires is
= I₃* B
= I₃*[-μ₀I₁/(2π*2d) + μ₋₀I₂/(2πd) + μ₀I₄/(2πd) + μ₀I₅/(2π*2d)] (+y direction)
Thus,
= μ₀I₃/(2πd) * (-I₁/2 + I₁ + I₄ + I₅/2)
Therefore, the magnitude of the net force per unit length acting on wire 3 due to the currents in the other wires is = 5.81*10-7 N/m
Answer:
If a body is moving with uniform velocity, acceleration is zero. So net force acting on it will be also zero. But the body has energy due to its constant motion.
Answer:
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Explanation:
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