Answer:
The speed of James is 0.776 m/s
Explanation:
Step 1: Data given
mass of James = 95.0 kg
mass of Ramon = 67.0 kg
We consider James and Ramon and the rope to a single system. This means that the net external forces on the system = 0
.The momentum = 0, so the sum of the momentum of each part must be 0 in total.
Step 2: Calculate the speed of James
m(james) *v(James) = m(Ramon) * v(Ramon)
with m(James) = the mass of James = 95.0 kg
with v(James) = speed of James = TO BE DETERMINED
with m(Ramon) = mass of Ramon = 67.0 kg
with v(Ramon) = speed of Ramon = 1.10 m/s
v(James) = (m(Ramon) * v(Ramon))/ m(james)
v(James) = (67.0 kg* 1.10 m/s) / 95.0 kg
v(James) = 0.776 m/s
The speed of James is 0.776 m/s
Chloroplasts and vacuoles
Answer:
γ = 0.06563 N / m
9.78% difference
Explanation:
Solution:-
- Surface tension is the ability of any fluid to resist any external force which causes a decreases in surface area of the impact area due to inward compressive forces. These compressive forces occur due to cohesive nature of the fluid molecules.
- Mathematically, surface tension ( γ ) is defined as the force felt per unit length by the fluid.
γ = F / L
Where,
F: Force imparted
L: The length over which force is felt
- We are given the mass ( M ) of ( n = 100 ) water droplets to e 3.78 g. The mass of a single droplet ( m ) can be evaluated as follows:
m = M / n
m = 3.78 / 100
m = 0.0378 g
- The force ( F ) imparted by a single drop of water from the burette can be determined from the force balance on a single droplet. Assuming the distance over which the drop falls is negligible and resistive forces are negligible. Then the only force acting on the droplet is due to gravity:
F = m*g
F = 0.0378*9.81*10^-3
F = 0.000370818 N
- The length over which the force is felt can be magnified into a circular area with diameter equal to that of a single droplet ( d ). The circumferential length ( L ) of the droplet would be as follows:
L = π*d
L = π*( 0.0018 )
L = 0.00565 m
- Then the surface tension would be:
γ = F / L
γ = 0.000370818 / 0.00565
γ = 0.06563 N / m
- The tabulated value of water's surface tension is given as follows:
γa = 0.07275 N/m
- We will determine the percentage difference between the value evaluated and tabulated value as follows:

- The %difference between is within the allowable practical limits of 10%. Hence, the evaluated value ( γ = 0.06563 N / m ) can be accepted with 9.78% error.
Answer:
Explanation:
AB = 110 miles
Let the distance of the western station from fire is d.
As according to the diagram, use Sine law

d = 110 x 0.2588 / 0.73
d = 39 miles
I think we will use the law of conservation of linear momentum;
M1V1 = M2V2
M1 = 4 kg (mass of the water balloon launcher)
V1=?
M2= 0.5 kg ( mass of the balloon)
V2 = 3 m/s
Therefore; 4 V1 = 0.5 × 3
4V1= 1.5
V1= 1.5/4
= 0.375 m/s