Which factors affect the gravitational force between objects? Check all that apply. difference in speed of objects direction of
2 answers:
distance between objects
masses of the objects
Explanation:
The magnitude of the gravitational force between two objects is given by
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is the distance between the two objects
By looking at the formula, we see that the gravitational force is affected only by two quantities:
- the masses of the objects, m1 and m2
- the distance between the objects, r
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Answer:
2352645198509.9604 m/s²
Explanation:
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
M = Mass of black hole =
= 10000+100 m
= Distance between the nose and the center of the black hole = 10000 m
The difference in the gravitational field in this system is given by
The acceleration is 2352645198509.9604 m/s²
A) The acceleration is due to gravity at any given point if you look at it vertically, so 
.
b)
, so 
. We use 
and then the final speed must be 0 because it stops at the highest point. So 
. Solve for 
and you get 
c)
, and then we plug the values: 
and we already have the time from "b)", so ![Y_m_a_x = [(32sin(25))*(32sin(25)/10)] - 5(32sin(25)/10)^2](https://tex.z-dn.net/?f=Y_m_a_x%20%3D%20%5B%2832sin%2825%29%29%2A%2832sin%2825%29%2F10%29%5D%20-%205%2832sin%2825%29%2F10%29%5E2)
; then we just rearrange it ![Y_m_a_x = 10[(32sin(25))^2/100] - 5 [(32sin(25))^2/100]](https://tex.z-dn.net/?f=Y_m_a_x%20%3D%2010%5B%2832sin%2825%29%29%5E2%2F100%5D%20-%205%20%5B%2832sin%2825%29%29%5E2%2F100%5D%20)
and finally ![Y_m_a_x = 5[(32sin(25))^2/100] = (32sin(25))^2/20](https://tex.z-dn.net/?f=Y_m_a_x%20%3D%205%5B%2832sin%2825%29%29%5E2%2F100%5D%20%3D%20%2832sin%2825%29%29%5E2%2F20)
b)
c)