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3 years ago

12

Which has a higher frequency, a neutron of electron? Why?

1 answer:

maria [59]3 years ago

6 0

Electron because of the charge it has

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What is a wave produced by vibrating electric charges that can travel in matter and empty space?

Harman [31]

The answer is A

Explanation:

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4 years ago

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You breathe in 12.0 L of pure oxygen at 298 K and 1,000 kPa to fill your lungs. How many moles of oxygen did you take in. Can yo

givi [52]

We are given with
V = 12L
T = 298 K
P = 1000 kPa

We are asked to get the number of moles, n

We can solve this using the ideal gas law
PV = nRT
n = PV / RT
Simply substitute the values and use the appropriate value for R.

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Why don’t metals break when pounded into sheets or drawn into wires

sergeinik [125]

Because metallic bonding is non-localized, and extends throughout the metallic lattice. Metal nuclei can move with respect to other metal nuclei without disrupting the forces of attraction.

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4 years ago

11. Assuming that the gases are ideal, calculate the amount of work done (joules) in each of the following reactions at 25 degre

gayaneshka [121]

<u>Answer:</u>

<u>For a:</u> Work done for the given reaction is 2477.572 J.

<u>For b:</u> Work done for the given reaction is 0 J

<u>Explanation:</u>

To calculate the work done for the reaction, we use the equation:

$W=-P\Delta V$

Ideal gas equation follows:

$PV=nRT$

Relating both the above equations, we get:

$W=-\Delta n_gRT$ ......(1)

where,

$\Delta n_g$ = difference in number of moles of products and reactants = $n_g_{(products)}-n_g_{(reactants)}$

R = Gas constant = 8.314 J/K.mol

T = temperature = $25^oC=[273+25]K=298K$

<u>For a:</u>

The chemical reaction follows:

$4HCl(g)+O_2(g)\rightarrow 2Cl_2(g)+2H_2O(g)$

$\Delta n_g=4-5=-1$

Putting values in equation 1, we get:

$W=-(-1mol)\times (8.314J/K.mol)\times 298K=2477.572J$

Hence, work done for the given reaction is 2477.572 J.

<u>For b:</u>

The chemical reaction follows:

$2NO(g)\rightarrow N_2(g)+O_2(g)$

$\Delta n_g=2-2=0$

Putting values in equation 1, we get:

$W=-(0mol)\times (8.314J/K.mol)\times 298K=0J$

Hence, work done for the given reaction is 0 J.

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3 years ago

Iron, an important component of the steel used in the construction of buildings, bridges, and railroads, combines with oxygen to

vladimir2022 [97]

I don't understand, what you want?

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4 years ago