Electrons are negatively charged particles that surround the atom's nucleus. Electrons were discovered by J. J. Thomson in 1897. *Protons are positively charged particles found within atomic nuclei.

Explanation:

6 0

3 years ago

2HgCl2(aq) + C2O42–(aq) → 2Cl–(aq) +2CO2(g) + Hg2Cl2(s)

alexgriva [62]

Explanation:

Expression for rate of the given reaction is as follows.

Rate = k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y[/tex]

Therefore, the reaction equations by putting the given values will be as follows.

$1.8 \times 10^{-5} = k[0.105]x [0.15]y$ ............. (1)

$7.2 \times 10^{-5} = k [0.105]x [0.30]y$ ........... (2)

$3.6 \times 10^{-5} = k [0.0525]x [0.30]y$ ............ (3)

Now, solving equations (1) and (2) we get the value of y = 2. Therefore, by solving equation (2) and (3) we get the value of x = 1.

Therefore, expression for rate of the reaction is as follows.

Rate = $k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y$

Rate = $k [HgCl2]1 [C_{2}O^{-2}_{4}]2$

Hence, total order = 1 + 2 = 3

According to equation (1),

$1.8 \times 10^{-5} = k[0.105]x [0.15]y$

$1.8 \times 10^{-5} = k [0.105]1 [0.15]2$

k = $7.6 \times 10^{-3} M^{-2} min^{-1}$

Thus, we can conclude that rate constant for the given reaction is $7.6 \times 10^{-3} M^{-2} min^{-1}$ .

8 0

2 years ago

What is an acid?

____ [38]

Answer:

A substance that produces hydrogen gas when dissolved

7 0

2 years ago

Calculate ΔHrxn for the following reaction: Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g) Use the following reactions and given ΔH′s. 2Fe(s)+3/

sesenic [268]

Answer:

The answer to your question is: ΔHrxm = -23.9 kJ

Explanation:

Data:

2Fe(s)+3/2O2(g)→Fe2O3(s), ΔH = -824.2 kJ (1)

CO(g)+1/2O2(g)→CO2(g) ΔH = -282.7 kJ (2)

Reaction:

Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)

We invert (1) and change the sign of ΔH

Fe2O3(s) → 2Fe(s)+3/2O2(g) ΔH = 824.2 kJ

We multiply (2) by 3

3( CO(g)+1/2O2(g)→CO2(g) ΔH = -282.7 kJ) (2)

3CO(g)+3/2O2(g)→3CO2(g) ΔH = -848.1 kJ

We add (1) and (2)

Fe2O3(s) → 2Fe(s)+3/2O2(g) ΔH = 824.2 kJ

3CO(g)+3/2O2(g)→3CO2(g) ΔH = -848.1 kJ

Fe2O3(s) + 3CO(g)+3/2O2(g) → 2Fe(s)+3/2O2 + 3CO2(g)

Simplify

Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g) and ΔHrxm = -23.9 kJ

6 0

2 years ago