Ask question

Ask question

All categories

3 years ago

5

You were tasked to check if the liquid sample you have is substance or a mixture.which among these tests is the BEST way to do s

o?
I.COLOR COMPARISON
II.TASTE COMPARISON
III.BOILING POINT TEST
IV.MELTING POINT TEST

A. 1,2,3,4
B. 1,2,3 ONLY
C.1,2,4 ONLY
D.1 AND 3 ONLY

1 answer:

mr Goodwill [35]3 years ago

7 0

D. 1 and 3 only because you never taste, and a liquid cannot melt

You might be interested in

The reaction 2a → a2 was experimentally determined to be second order with a rate constant, k, equal to 0.0265 m–1min–1. if

katovenus [111]

The integrated rate law for a second-order reaction is given by:

$\frac{1}{[A]t} = \frac{1}{[A]0} + kt$

where, [A]t= the concentration of A at time t,

[A]0= the concentration of A at time t=0

<span>k =</span> the rate constant for the reaction

<u>Given</u>: [A]0= 4 M, k = 0.0265 m–1min–1 and t = 180.0 min

Hence, $\frac{1}{[A]t} = \frac{1}{4} + (0.0265 X 180)$

<span> = 4.858</span>

<span><span><span>Therefore, [A]</span>t</span>= 0.2058 M.</span>

<span>
</span>

<span>Answer: C</span>oncentration of A, after 180 min, is 0.2058 M

7 0

3 years ago

Read 2 more answers

What is the concentration of a solution with a volume of 660L that contains 33.4g of AlCO3?

lana [24]

Answer:

The concentration of the solution is 5.8168 × $10^{-4}$ mol. $dm^{-3}$

Explanation:

Here, we want to calculate the concentration of the solution.

The unit of this is mol/dm^3

So the first thing to do here is to calculate the number of moles of the solute present, which is the number of moles of AlCO3

The number of moles = mass/molar mass

molar mass of AlCO3 = 27 + 12 + 3(16) = 27 + 12 + 48 = 87g/mol

Number of moles = 33.4/87 = 0.384 moles

This 0.384 moles is present in 660 L

x moles will be present in 1 dm^3

Recall 1 dm^3 = 1L

x * 660 = 0.384 * 1

x = 0.384/660 = 0.00058168 = 5.8168 * 10^-4 mol/dm^3

7 0

3 years ago

4. Consider a 33.0 mL solution containing 0.0758 M NaF and 0.0955 M HF. What is the total number of moles of HF after the additi

Ostrovityanka [42]

Buffer solution resist the change in pH upon addition of small amount of strong acid or strong base.
Buffer consists of weak acid as HF / and its conjugate base NaF
When strong acid as HCl is added to buffer, it respond with its conjugate base to convert the strong acid to weak acid like this:
HCl (S.A) + NaF → NaCl + HF (W.A)
moles of HF we already have = M * V(in liters)
= 0.0955 M * 0.033 L = 3.15 x 10⁻³ mole
moles of HCl added = 8.00 x 10⁻⁵ mole
one mole HCl reacts with 1 mole NaF to give 1 mole HF
so the amount added to HF = 8.00 x 10⁻⁵
Total moles of HF present = (3.15 x 10⁻³) + (8.00 x 10⁻⁵) = 3.23 x 10⁻³ mole

4 0

3 years ago

A scuba diver that ascends to the surface too quickly can experience decompression sickness, which occurs when nitrogen that dis

Butoxors [25]

Answer:

The factor that will change the volume of the diver's lungs upon reaching the surface is 4

Explanation:

Given data:

Pressure increases 1 atm = 101.325 kPa

34 ft = 10.3632 m

Depth of 102 ft = 31.0896 m

Question: What factor will the volume of the diver's lungs change upon arrival at the surface, V₂/V₁ = ?

The pressure at 31.0896 m:

$P_{1} =101.325+(\frac{31.0896}{10.3632} *101.325)=405.3kPa$

The factor will the volume of the diver's lungs change upon arrival at the surface:

$\frac{V_{2}}{V_{1} } =\frac{P_{1}}{P_{2}} =\frac{405.3}{101.325} =4$

5 0

3 years ago

A sample of ch4o with a mass of 32.0 g contains ________ molecules of ch4o.

ValentinkaMS [17]

6.02 times 10 to the 23 power, which is Avogadros number

3 0

3 years ago