Iron in rock combining with oxygen to form hematite

Sixty-three grams of copper reacted with 32 grams of sulfur. this chemical reaction produced the compound copper sulfide. what w

Nuetrik [128]

The mass of, $Cu_2S$ , compound formed is 77.9g

62 grams of copper reacted with 32grams of sulfur to form copper sulfide.

$Cu + S_2 \rightarrow CuS_2$

stoichiometry of Cu to S is 2:1

We need to find the limiting reactant

Molar mass of copper = 63.5 g/mol

Molar mass of Sulfur = 32 g/mol

Number of moles of Copper = $\dfrac{mass} {molar mass } = 0.99mole$

Number of moles of Sulfur = $\dfrac{mass} {molar mass} = \dfrac{32g} {32g/mol} = 1 mole$

Since copper have lesser number of moles, therefore the limiting reagent is copper so the amount of product formed depends on amount of Cu present

stoichiometry of Copper to $Cu_2S$ is 2:1

0.99 mol of Copper forms = $\dfrac{0.99} {2}$ = 0.49 mol of $Cu_2S$

Mass of $Cu_2S$ produced = Number of moles $\times$ Molar mass

Mass of $Cu_2S$ produced = 0.49 mol $\times$ 159 g/mol = 77.9g

Learn more about limiting reagent here-

brainly.com/question/9913056

#SPJ4

6 0

2 years ago

How to solve partial pressure given water vapor pressure?

CaHeK987 [17]

The partial pressure of water in the mixture, Pwater, is the equilibrium vapour pressure of water at the temperature specified. At 298 K, from the data at the beginning of the questions section, Pwater = 3.17 kPa. Using the Ideal Gas Equation, the number of moles of N2 can be calculated.

6 0

3 years ago

What is y'alls favorite Call of Duty Zombies map?

mylen [45]

Answer:

Hello! Jaesuk~Sakai Here!! UwU

Explanation:

my fav cod map, is the one with the deck near the ocean ^^

ps: u do know which one i'm talking about, right? 

pls help me out if u know wat map i'm talking about so i can edit this answer for u ^^

4 0

3 years ago

Read 2 more answers

It takes 11.2 kj of energy to raise the temperature of 145 g of benzene from 22.0°c to 67.0°c. what is the specific heat of benz

Cloud [144]

We can use the heat equation,
Q = mcΔT

where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).
Q = 11.2 kJ = 11200 J
m = 145 g
c = ?
ΔT = (67 - 22) °C = 45 °C
By applying the formula,
11200 J = 145 g x c x 45 °C
c = 1.72 J g⁻¹ °C⁻¹

Hence, specific heat of benzene is 1.72 J g⁻¹ °C⁻¹.

7 0

3 years ago

How many milliliter are in 0.063 L

Trava [24]

Answer:

63 mL

Explanation:

To find the amount of mililiters in an amount of liters, we must multiply by the amount of liters by 1000.

0.063 L × 1000 = 63 mL

3 0

3 years ago

Read 2 more answers