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SVEN [57.7K]
3 years ago
11

A ball is thrown straight up in the air. For which situations are both the instantaneous velocity and the acceleration zero? (Se

lect all that apply.)
Physics
1 answer:
Gwar [14]3 years ago
6 0

Answer:

Therefore, the situation in which both the instantaneous velocity and acceleration become zero, is the situation when the ball reaches the highest point of its motion.

Explanation:

When a ball is thrown upward under the free fall action of gravity, it starts to loose its Kinetic Energy as it moves upward. As the ball moves in upward direction, its kinetic energy gradually converts into its potential energy. As a result the speed of the ball starts to decrease as it moves up. Therefore, at the highest point during its motion, the velocity of ball becomes zero and it stops at the highest point for a moment, and then it starts to fall back down, under the influence of gravitational force.

Therefore, the situation in which both the instantaneous velocity and acceleration become zero, is the situation <u>when the ball reaches the highest point of its motion.</u>

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State the career function of chemical engineering​
Arte-miy333 [17]

Answer:

Chemical engineers develop and design chemical manufacturing processes. They apply the principles of chemistry, biology, physics, and math to answer problems that involve the production of chemicals, fuel, drugs, food, and many products

Explanation:

7 0
3 years ago
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A singly charged ion (q=−1.6×10−19) makes 7.0 rev in a 45 mT magnetic field in 1.29 ms. The mass of the ion in kg is
insens350 [35]

Answer:

m=1.47\times 10^{-24}\ Kg

Explanation:

Given that,

Charge, q=1.6\times 10^{-19}\ C

Revolution = 7 rev

magnetic field, B = 45 mT

Time, t = 1.29 ms

We need to find the mass of the ion. Let m be the mass. The formula for the mass in terms of time period is given by :

m=\dfrac{qBT}{2\pi}\\\\m=\dfrac{1.6\times 10^{-19}\times 45\times 10^{-3}\times 1.29\times 10^{-3}}{2\pi}\\\\m=1.47\times 10^{-24}\ Kg

So, the mass of the ion is equal to 1.47\times 10^{-24}\ Kg.

4 0
3 years ago
A horizontal disk with a radius of 10 cm rotates about a vertical axis through its center. The disk starts from rest at t = 0 an
Tom [10]

Answer:

0.69s

Explanation:

10 cm = 0.1 m

Let t be the time that radial and tangential components of the linear acceleration of a point on the rim be equal in magnitude. At that time we have the angular velocity would be

\omega = \alpha t = 2.1 t

And so the radial acceleration is

a_r = \omega^2 r = (2.1t)^2 r = 2.1^2 t^2 * 0.1= 0.441 t^2 m/s^2

The tangential acceleration is always the same since angular acceleration is constant:

a_t = \alpha * r = 2.1 * 0.1 = 0.21 m/s^2

For these 2 quantities to be the same

a_r = a_t

0.441 t^2 = 0.21

t^2 = 0.21/0.441 = 0.4762

t = \sqrt{0.4762} = 0.69 s

6 0
3 years ago
. The p.d. at the terminals of a battery is 25V when no load is connected and 24V when a load taking 10A is connected. Determine
makvit [3.9K]

Answer:

the internal resistance of the cell is 0.1 ohm.

Explanation:

Given;

p.d at the terminals of a battery at no load, E₁ = 25 V

p.d at the terminals of a battery at a load, E₂ = 24 V

current through the circuit, I = 10 A

The potential drop across the circuit, V = E₁ - E₂

                                                              = 25 V -  24 V

                                                               = 1 V

The internal resistance of the cell is calculated as follows;

r = V/I

r = 1 / 10

r = 0.1 ohm

Therefore, the internal resistance of the cell is 0.1 ohm.

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3 years ago
How do you write the scientific name delis cactus correctly
Talja [164]
Delis cactus is the correct way to write it.
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