Question

A 50kg block slides down a slope that forms an angle of 54 degrees if it is known that when descending it has a force of 40N and a coefficient of friction of 0.33. What is the acceleration in the block?

Answer 1

Answer:

The acceleration in the block is 2.1 m/s²

Explanation:

Given that,

Mass = 50 kg

Angle = 54°

Force = 40 N

Coefficient of friction = 0.33

We need to calculate the acceleration in the block

Using balance equation

$F_{net}=F_{f}-F\cos\theta$

$ma=\mu mg\sin\theta-F\cos\theta$

$a=\dfrac{\mu mg\sin\theta-F\cos\theta}{m}$

Put the value into the formula

$a=\dfrac{0.33\times50\times9.8\sin54-40\cos54}{50}$

$a=2.1\ m/s^2$

Hence, The acceleration in the block is 2.1 m/s²