Answer:
![8.36541\times 10^{56}](https://tex.z-dn.net/?f=8.36541%5Ctimes%2010%5E%7B56%7D)
Explanation:
Mass of the sum = ![2\times 10^{30}\ kg](https://tex.z-dn.net/?f=2%5Ctimes%2010%5E%7B30%7D%5C%20kg)
70% of this mass is
![0.7\times 2\times 10^{30}=1.4\times 10^{30}\ kg](https://tex.z-dn.net/?f=0.7%5Ctimes%202%5Ctimes%2010%5E%7B30%7D%3D1.4%5Ctimes%2010%5E%7B30%7D%5C%20kg)
Mass of hydrogen in the sun is ![1.4\times 10^{30}\ kg](https://tex.z-dn.net/?f=1.4%5Ctimes%2010%5E%7B30%7D%5C%20kg)
Mass of a hydrogen atom = ![1.6735575\times 10^{-27}\ kg](https://tex.z-dn.net/?f=1.6735575%5Ctimes%2010%5E%7B-27%7D%5C%20kg)
Dividing the mass hydrogen in the sun by the mass of one hydrogen atom will give us the number of hydrogen atoms
![\frac{1.4\times 10^{30}}{1.6735575\times 10^{-27}}=8.36541\times 10^{56}](https://tex.z-dn.net/?f=%5Cfrac%7B1.4%5Ctimes%2010%5E%7B30%7D%7D%7B1.6735575%5Ctimes%2010%5E%7B-27%7D%7D%3D8.36541%5Ctimes%2010%5E%7B56%7D)
The number hydrogen atoms in the Sun is ![8.36541\times 10^{56}](https://tex.z-dn.net/?f=8.36541%5Ctimes%2010%5E%7B56%7D)
Answer:
Distance, S = 13m
Explanation:
Given the following data;
Initial velocity, u = 4m/s
Final velocity, v = 9m/s
Time, t = 2 seconds
To find the distance, S;
First of all, we would determine the acceleration of the shark.
Acceleration = (v - u)/t
Acceleration = (9 - 4)/2
Acceleration = 5/2
Acceleration = 2.5m/s²
Now, to find the distance we would use the second equation of motion
S = ut + ½at²
Substituting into the equation, we have
S = 4(2) + ½*2.5*2²
S = 8 + 1.25*4
S = 8 + 5
Distance, S = 13m
The correct answer is C. Even though the potential energy can be stored, but it is connected with coordinate system.
Answer:
Part 1. 4. 56 mi/h; Part 2. 7. 16 mi/h south; Part 3. 6. 56 mi/h north
Explanation:
Part 1. Average speed
Speed = distance/time
Distance = Austin-Waco + Waco-Austin + Austin-San Antonio
= 100 mi + 100 mi + 80 mi = 280 mi
Time = 5 h
Speed = 280 mi/5 h = 56 mi/h
Part 2. Average velocity
Velocity is a vector. It includes both speed and direction.
Assume south is positive and north is negative.
Distance = -100 mi + 100 mi + 80 mi = +80 mi
Velocity = +80 mi/5h = +16 mi/h = 16 mi/h south
Part 3. Average velocity Austin-Waco
Distance = north
If the student kept to an average speed of 56 mi/h, the average velocity was 56 mi/h north.