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3 years ago

What did the biologist wear on his first date ?

Physics

1 answer:

LiRa [457]3 years ago

6 0

Answer:

Calvin Cycles

Explanation:

This is a popular joke. Is this an answer choice for your question?

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The diagram below shows the movement of matter in a portion of the water cycle.

Alisiya [41]

Answer:

d) precipitation

Hope it helps you

And if you want to, pls mark it as the brainliest answer

7 0

3 years ago

Why is work measured in

erastova [34]

Answer:

C) the equation consists of two factors:

work = force * distance

W = F · S

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2 years ago

If a car increases its velocity from 1m/s to 3.6km/hr in 5 seconds what’s its acceleration

EleoNora [17]

Answer:

applying 1st eq of motion vf=vi+at here we have to find a=vf-vi/t , a= 1-1/5 , a=0/5 then we got a=0 here(vf value 3.6km/h is converted in standard unit 3.6×1000/3600 so we get vf=1m/s²

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3 years ago

The total charge a battery can supply is rated in mA⋅hmA⋅h, the product of the current (in mA) and the time (in h) that the batt

Nat2105 [25]

Answer:

118800 seconds

Explanation:

Given :

Voltage, V = 1.2 V

Resistance, R = 22 Ω

Applying Ohm's law, we get

Voltage, V = IR

Current $I=\frac{V}{R}$

$I=\frac{1.2}{22}$

I = 0.0545 A

Rate = 1800 mAh

Time taken, $t=\frac{1800 \times 10^{-3}}{0.0545}$

= 33 hr

= 118800 s

8 0

3 years ago

The Hubble Space Telescope orbits the Earth at approximately 612,000m altitude. Its mass is 11,100 kg and the mass of earth is 5

nexus9112 [7]

Answer:

7.55 km/s

Explanation:

The force of gravity between the Earth and the Hubble Telescope corresponds to the centripetal force that keeps the telescope in uniform circular motion around the Earth:

$G\frac{mM}{R^2}=m\frac{v^2}{R}$

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2}$ is the gravitational constant

$m=11,100 kg$ is the mass of the telescope

$M=5.97\cdot 10^{24} kg$ is the mass of the Earth

$R=r+h=6.38\cdot 10^6 m+612,000 m=6.99\cdot 10^6 m$ is the distance between the telescope and the Earth's centre (given by the sum of the Earth's radius, r, and the telescope altitude, h)

v = ? is the orbital velocity of the Hubble telescope

Re-arranging the equation and substituting numbers, we find the orbital velocity:

$v=\sqrt{\frac{GM}{R}}=\sqrt{\frac{(6.67\cdot 10^{-11})(5.97\cdot 10^{24} kg)}{6.99\cdot 10^6 m}}=7548 m/s=7.55 km/s$

6 0

3 years ago

What did the biologist wear on his first date ?​

What did the biologist wear on his first date ?