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Scorpion4ik [409]
3 years ago
13

Points for free

Engineering
2 answers:
Sphinxa [80]3 years ago
6 0

vielen Dank <3

thanks much <3

gulaghasi [49]3 years ago
3 0

Answer:

THANK YOUUUUU!!!!!

Explanation:

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Given the system of equations−3x2+7x3=2,x1+2x2–x3=3,5x1−2x2=2(a). Compute the determinant. (b). Use Cramer’s rule to solve for t
34kurt

Answer:

(x1,x2,x3)=(0.985507,1.463768,0.913043)

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3 years ago
The acrylic plastic rod is 200 mm long and 15 mm in diameter. If an axial load of 300 N is applied to it, determine the change i
ehidna [41]

Answer:

Change in length = 0.1257 mm

Change in diameter= -0.03771mm

Explanation:

Given

Diameter, d = 15 mm

Length of rod, L = 200mm

F = Force= 300N

d = 0.015m

Ep=2.70 GPa, np=0.4.

First, we have to calculate the normal stress using

σ = F/A where F = Force acting on the Cross-sectional area

A = Area

Area is calculated as πd²/4 where d = 0.015m

A = 22/7 * 0.015²/4

A = 0.000176785714285m²

A = 1.768E-4m²

So, stress. σ = 300N/1.768E-4m²

σ = 1696832.579185520Pa

σ = 1.697MPa

Calculating E(long)

E(long) = σ /Ep

E(long) = 1.697E-3/2.70

E(long) = 0.0006285

At this point, we fan now calculate the change in length of the element;

∆L = E(long) * L

∆L = 0.0006285 * 200mm

∆L = 0.1257mm

Calculating E(lat)

E(lat) = -np * E(long)

E(lat) = -4 * 0.0006285

E(lat) = -0.002514

At this point, we can now calculate the change in diameter of the element;

∆D = E(lat) * D

∆L = -0.002514 * 15mm

∆L = -0.03771mm

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