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3 years ago

Points for free

Engineering

2 answers:

Sphinxa [80]3 years ago

6 0

vielen Dank <3

thanks much <3

gulaghasi [49]3 years ago

3 0

Answer:

THANK YOUUUUU!!!!!

Explanation:

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pump delivers 11000 lb/hr of water from an elevation 30 ft below the pump to an elevation 50 ft above the pump through various d

mojhsa [17]

Answer:

good luck

Explanation:

4 0

3 years ago

6.3 In a particular technology, a small BJT operating at conducts a collector current of 100 μA. What vBE = 28VT is the correspo

laiz [17]

Answer:

Saturation current

Isi = 6.91 * 10^-17 A

The saturation current Is2 of transistor Q2 is 2.2 * 10-15 A

Collector current Ic2 at Vbe2 is 3.2mA

Base emitter voltage Vbe2 is 26.84 VT

Explanation:

Complete question is as follows;

Problem 6.3: In a particular technology, a small BJT operating at vBE = 28VT conducts a collector current of 100

µA. What is the corresponding saturation current?

For a transistor in the same technology but with an emitter junction that is 32 times larger, what is the saturation

current?

What current will this (second) transistor conduct at vBE = 28VT ?

What is the base-emitter voltage of the latter transistor at iC = 1 mA? Assume active-mode operation in all cases.

solution;

Please check attachment for complete solution and step by step explanation

4 0

3 years ago

What is one advantage corporations have over other types of businesses

SpyIntel [72]

Liability, easy transferring of owner ships

4 0

3 years ago

Xfsfdgdgsdgdsgsdsgdsdgsdsg

bulgar [2K]

answer:

okay, thanks for the points tho.

3 0

3 years ago

Read 2 more answers

An ideal Otto cycle has a compression ratio of 7. At the beginning of the compression process, P1 = 90 kPa, T1 = 27°C, and V1 =

Ainat [17]

Answer:

i) Heat rejection = 1.0288 KJ

Network production = 1.212 kJ

ii) Thermal efficiency = 54.08%

mean effective pressure = 353.5 kPa

Explanation:

Given data :

Compression ratio ( r ) = 7

P1 ( initial pressure ) = 90 kPa,

T1 ( initial temperature ) = 27°C + 273 = 300 K

V1 = 0.004 m^3

Max cycle Temperature = 1127°C for each repetition of the cycle

i) Determine the heat rejection and net work production

considering that process 1-2 is an Isentropic compression

Find ; T2 = T1 ( r )^1.4-1

T2 = 300 ( 7 )^0.4 = 653.371 K

P2 = P1( r )^k

= 90 ( 7 )^1.4 = 1372.081 kPa

considering that process 3-4 is an Isentropic expansion

T4 = T3 / r^k-1

= 1400 / 7^(1.4 -1 ) = 642.82 K

Next ; Calculate the value of m

m = P1V1 / RT1 = 90(0.004) / 0.287 ( 300 )

m = 4.18 * 10^-3 kg

Finally :

amount of heat rejected = mCv ( T4 - T1 )

= 4.18 * 10^-3 ( 0.718 ) ( 642.82 - 300 )

Qout = 1.0288 KJ

amount of heat added ( Qin ) = mCv ( T3 - T2 )

= 4.18 * 10^-3 ( 0.718 ) ( 1400 - 653.371 )

hence Qin = 2.2408 kJ

Network production( Wnet) = Qin - Qout

= 2.2408 - 1.0288 ) KJ

= 1.212 kJ

ii) Determine the thermal efficiency and mean effective pressure of the cycle

Thermal efficiency = 1 - Qout / Qin

= 1 - ( 1.0288 / 2.2408 ) = 54.08%

mean effective pressure = Wnet / V1 ( 1 - 1/r )

= 1.212 / 0.004 ( 1 - 1/7 )

= 353.5 kPa

8 0

3 years ago