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3 years ago

HELPWILLGIVEBRAINLIEST！！！

Physics

2 answers:

DENIUS [597]3 years ago

5 0

Answer:

It’s D

Explanation:

Andreas93 [3]3 years ago

3 0

Answer:

Explanation:

Since there is less water in the first beaker, there is a higher concentration of red dots in it compared to the second beaker.

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Made use of the whole time scale

muminat

Answer:

What're you trying ask

Explanation:

7 0

3 years ago

Read 2 more answers

A certain electric circuit obeys Ohm's law. If the resistance of the circuit is doubled, what will happen to the current through

netineya [11]

Answer:

currrent will be halved

Explanation:

v = ir

v/r = i multiply both sides by 1/ 2

v / (2r) = 1/2 i

4 0

3 years ago

A net force applied to a 15.0 kg box produced an acceleration of 4.2 m/s2. If the same net force was applied to a 10 kg box, wha

igor_vitrenko [27]

Answer:

$6.3\ m/s^2$

Explanation:

Given that,

If the mass of a body is 15 kg and produced an 4.2 m/s², we need to find the acceleration if the mass is 10 kg and the same force is applied.

Force is given by :

F = ma

Since force is same

$m_1a_1=m_2a_2\\\\a_2=\dfrac{m_1a_1}{m_2}\\\\a_2=\dfrac{15\times 4.2}{10}\\\\a=6.3\ m/s^2$

So, if the mass is 10 kg, acceleration is $6.3\ m/s^2$

8 0

3 years ago

A mass of 0.4 kg hangs motionless from a vertical spring whose length is 0.95 m and whose unstretched length is 0.65 m. Next the

nexus9112 [7]

Answer:

Explanation:

spring constant of spring = mg / x

= .4 x 9.8 / ( .95 - .65 )

=13.07 N / m

energy stored in spring = 1/2 k x²

= .5 x 13.07 x ( 1.2 - .65 )²

= 1.976 J

Let it goes x m beyond its equilibrium position

Total energy at initial point

= 1.976 + 1/2 m v²

= 1.976 + .5 x .4 x 1.6²

= 2.488 J

energy at final point

= mgh + 1/2 k x²

.4 x 9.8 x ( .55 + x ) + .5 x 13.07 x² = 2.488

6.535 x² + 2.156 + 3.92 x = 2.488

6.535 x² + 3.92 x - .332 = 0

x = .075 m

7.5 cm

4 0

3 years ago

A single-turn circular loop of radius 14 cm is to produce a field at its center that will just cancel the earth's magnetic field

Olin [163]

Answer:

49 A

Explanation:

We are given that

Number of turns,N=1

Radius,r=14 cm= $\frac{14}{100}=0.14 m$

1 m=100 cm

Magnetic field,B=0.7 G= $0.7\times 10^{-4} T$

$1G=10^{-4} T$

$\mu_0=4\pi\times 10^{-7} Tm/A$

We know that magnetic field

$B=\frac{\mu_0IN}{2\pi r}$

Substitute the values

$0.7\times 10^{-4}=\frac{4\pi\times 10^{-7}\times 1\times I}{2\pi\times 0.14}$

$I=\frac{0.7\times 10^{-4}\times 2\pi\times 0.14}{4\pi\times 10^{-7}\times 1}$

$I=49A$

6 0

3 years ago