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Ainat [17]
3 years ago
12

A weight of 15 N is located at a distance of 2.5 meters from the fulcrum of a simple lever. At what distance from the fulcrum sh

ould a weight of 20.0 N be placed on the opposite side of the fulcrum to balance the system?
Physics
1 answer:
tester [92]3 years ago
3 0

Answer:

The distance is 1.875 m away from the fulcrum of yhe simple lever

Explanation:

Clock wise moment = anti-clock wiseo moment.

Let's the distance to be determined be x...and let's assume x to be on the left.

15*2.5 = 20*x

37.5 = 20x

37.5/20 = x

1.875 = x

The distance is 1.875 m away from the fulcrum of yhe simple lever

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A watermelon is dropped off of a 50 ft bridge, and it explodes upon impact with the ground. How fast was it traveling in mph upo
Drupady [299]

Answer: 56.72 ft/s

Explanation:

Ok, initially we only have potential energy, that is equal to:

U =m*g*h

where g is the gravitational acceleration, m the mass and h the height.

h = 50ft and g = 32.17 ft/s^2

when the watermelon is near the ground, all the potential energy is transformed into kinetic energy, and the kinetic energy can be written as:

K = (1/2)*m*v^2

where v is the velocity.

Then we have:

K = U

m*g*h = (m/2)*v^2

we solve it for v.

v = √(2g*h) = √(2*32.17*50) ft/s = 56.72 ft/s

6 0
3 years ago
Near the end of a marathon race, the first two runners are separated by a distance of 45.6 m. The front runner has a velocity of
morpeh [17]

Answer:17.08 s

Explanation:

Given

distance between First and second Runner is 45.6 m

speed of first runner(v_1)=3.1 m/s

speed of second runner(v_2)=4.65 m/s

Distance between first runner and finish line is 250 m

Second runner need to run a distance of 250+45.6=295.6 m

Time required by second runner t=\frac{295.6}{4.65}=63.56 s

time required by first runner to reach finish line=\frac{250}{3.1}=80.64 s

Thus second runner reach the finish line 80.64-63.56=17.08 s earlier

3 0
3 years ago
A sled of mass m is being pulled horizontally by a constant horizontal force of magnitude F. The coefficient of kinetic friction
steposvetlana [31]

Answer:

The average velocity of the sled is vavg = s/t.

Explanation:

Hi there!

The average velocity is calculated as the traveled distance over time:

vavg = Δx/Δt

Where:

vavg = average velocity.

Δx = traveled distance.

Δt = elapsed time.

We already know the traveled distance (s) and also know the time it takes the sled to travel that distance (t). Then, the average velocity can be calculated as follows:

vavg = s/t

Have a nice day!

6 0
3 years ago
What conditions made it possible for earth's interior to separate into layer?
mamaluj [8]

Answer:

Separation of the Earth into layers (crust, mantle, inner core, and outer core) was largely caused by gravitational differentiation (separating different constituents at temperature where materials are liquid or plastic, owing to differences in density) early in Earth's history.

Explanation:

hoped it helped!!

7 0
2 years ago
A car starts from rest and goes down a slope with a constant
GREYUIT [131]

Answer:

25m/s

Explanation:

here we use 1st equation of motion

then we find this ans

3 0
2 years ago
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