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Vlad [161]
3 years ago
12

You are roller-skating at 3 m/s west, and your friend is roller-skating at 3 m/s east. What is your friend's velocity relative t

o you
Physics
2 answers:
Hatshy [7]3 years ago
8 0

If you use your ruler and clock to measure your friend's speed and direction WHILE you're skating along, you'll decide that your friend is skating away from you toward the East, at 6 m/s .

Alenkasestr [34]3 years ago
5 0

Answer:

9 m/s towards east

Explanation:

Consider east direction as positive and west direction as negative. A person is roller skating at 3 m/s west that is -3 m/s. His friend is moving at +3m/s

The relative velocity of object a with respect to be b can be calculated as follows:

v_{ab} = v_b-v_a\\ v_r=(3 - (-3)) m/s = 9 m/s towards East.

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In an economy, the demand for labor is given by the equation W = 15 - (1/200) L and the supply of labor is given by the equation
mr_godi [17]

Answer:

the equilibrium wage rate is 10  and the equilibrium quantity of labor is 1000 workers

Explanation:

The equilibrium wage rate and the equilibrium quantity of labor are found as the point where the equation of demand intercepts the equation of supply, so the equilibrium quantity of labor is:

W_{Demand} = W_{Supply}

15 - (1/200) L = 5 + (1/200) L

15 - 5 =  (1/200) L +  (1/200) L

10 = (2/200) L

(10*200)/2 = L

1000 = L

Then, the equilibrium wage rate is calculated using either the equation of demand for labor or the equation of supply of labor. If we use the equation of demand for labor, we get:

W = 15 - (1/200) L

W = 15 - (1/200) 1000

W = 10

Finally, the equilibrium wage rate is 10 and the equilibrium quantity of labor is 1000 workers

7 0
3 years ago
The product side of a chemical reaction is shown. → 7Ti2(SO4)3
Alex_Xolod [135]
The answer is the fourth choice because there are 7 represents in a coefficient.

7 0
3 years ago
Read 2 more answers
FORMULA PLEASE AND explINATION
Alex_Xolod [135]

2 Newtons to the right.

3 newtons are needed to over come the friction. There are 2 left over.

So the answer is 2 newtons to the right.

5 - 3 = 2

7 0
3 years ago
A solid uniform ball of mass 1.0 kg and radius 1.0 cm starts from rest and rolls down a 1.0-m high ramp. there is enough frictio
Luba_88 [7]
The correct answer is A
4 0
3 years ago
A ball is launched with initial speed v from the ground level up a frictionless hill. The hill becomes steeper as the ball slide
Triss [41]

Answer:

H(max) = (v²/2g)

Explanation:

The maximum height the ball will climb will be when there is no friction at all on the surface of the hill.

Normally, the conservation of kinetic energy (specifically, the work-energy theorem) states that, the change in kinetic energy of a body between two points is equal to the work done in moving the body between the two points.

With no frictional force to do work, all of the initial kinetic emergy is used to climb to the maximum height.

ΔK.E = W

ΔK.E = (final kinetic energy) - (initial kinetic energy)

Final kinetic energy = 0 J, (since the body comes to rest at the height reached)

Initial kinetic energy = (1/2)(m)(v²)

Workdone in moving the body up to the height is done by gravity

W = - mgH

ΔK.E = W

0 - (1/2)(m)(v²) = - mgH

mgH = mv²/2

gH = v²/2

H = v²/2g.

7 0
3 years ago
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