Answer:
T2= 7.3°C
Explanation:
To solve this problem we will use Charles law equation i.e,
V1/T1 = V2/T2
Given data
V1 = 269.7 L
T1 = 6.12 °C
V2= 320.4 L
T2=?
Solution:
Now we will put the values in equation
269.7 L / 6.12°C = 320.4 L / T2
T2= 320.4 L × 6.12°C/ 269.7 L
T2= 1960.85 °C. L /269.7 L
T2= 7.3°C
Bromine, B2. Hope this helps! ♥
Molality can be expressed by moles of solute over
kilograms of solvent. The question asks the molality of 0.25m NaCl. 0.25m NaCl
is equal to 0.25 moles of NaCl over 1 kg of water.
A) both potential and Kinect Energy. Because energy is stored in the covalent bonds holding atoms together in the form of molecules. This is a form of kinetic energy and the more the molecules move the more kinetic energy they have.