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Alborosie
1 year ago
7

three disaccharides are important in the human diet: sucrose, lactose, and maltose. click and drag the monosaccharides to build

each of the disaccharides below.
Chemistry
1 answer:
Paul [167]1 year ago
8 0

The monosaccharides to build each of the disaccharides are:

Glucose + fructose = sucrose

Galactose + glucose = lactose

glucose + glucose = maltose

What are monosaccharides examples?

The simplest carbohydrates, also called simple sugars, are plentiful in fruits. A monosaccharide is a carbohydrate consisting of one sugar unit.

What are the 4 monosaccharides?

Glucose is the most abundant monosaccharide. Galactose, mannose, fructose, and ribose are also of major biological importance.

What are the 3 disaccharides?

Disaccharides consist of two monosaccharide units, linked together with glycosidic bonds in the α or β orientation. The most important of them are sucrose, lactose, and maltose.

What are disaccharides and their functions?

Disaccharides act as an energy source for the body, just like any other carbohydrate. When we eat foods that contain disaccharides, our bodies break them down into simple sugars (monosaccharides) for absorption in the small intestine.

To know more about monosaccharides and disaccharides:

brainly.com/question/731310

#SPJ4

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Gaseous methane (CH4) will react with gaseous oxygen (O2) to produce gaseous carbon dioxide (CO) and gaseous water (H2O) . Suppo
Leto [7]

Answer:

0 g.

Explanation:

Hello,

In this case, since the reaction between methane and oxygen is:

CH_4+2O_2\rightarrow CO_2+2H_2O

If 0.963 g of methane react with 7.5 g of oxygen the first step is to identify the limiting reactant for which we compute the available moles of methane and the moles of methane consumed by the 7.5 g of oxygen:

n_{CH_4}=0.963gCH_4*\frac{1molCH_4}{16gCH_4}=0.0602molCH_4\\ \\n_{CH_4}^{consumed}=7.5gO_2*\frac{1molO_2}{32gO_2}*\frac{1molCH_4}{2molO_2} =0.117molCH_4

Thus, since oxygen theoretically consumes more methane than the available, we conclude the methane is the limiting reactant, for which it will be completely consumed, therefore, no remaining methane will be left over.

left\ over=0g

Regards.

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3 years ago
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3 years ago
Acetic acid (HC2H3O2) is the active ingredient in vinegar. Calculate the mass percent composition of O in acetic acid.
skelet666 [1.2K]

Answer:

53.29% of acetic acid is Oxygen

Explanation:

Step 1: Given data

Acetic acid it's molecular formula is HC2H3O2. This means it consists of 3 elements Carbon, Hydrogen and oxygen.

Step 2: the molar masses

The molecular mass of acetic acid is:

4* H = 4* 1.01 g/mole

2* C = 2*12 g/mole

2*O = 2* 16 g/mole

Total molar mass = 4+ 24+32 = 60.052 g/mole

Step 3: Calculate the mass percent

32 g of the 60.052 g is Oxygen

(32/60.052) *100% = 53.29%

53.29% of acetic acid is Oxygen.

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