Answer:
D, the acceleration of A is twice that of b.
Explanation: in four seconds b got to ten, in two seconds a got to 20. Going 10m/s faster in half the time is going twice the acceleration
Answer:
1.The main advantage of an electromagnet over a permanent magnet is that the magnetic field can be quickly changed by controlling the amount of electric current in the winding. However, unlike a permanent magnet that needs no power, an electromagnet requires a continuous supply of current to maintain the magnetic field.
1 is b because a runs 20 and b rus 102 is c
Answer:
a) The maximum height the ball will achieve above the launch point is 0.2 m.
b) The minimum velocity with which the ball must be launched is 4.43 m/s or 0.174 in/ms.
Explanation:
a)
For the height reached, we use 3rd equation of motion:
2gh = Vf² - Vo²
Here,
Vo = 3.75 m/s
Vf = 0m/s, since ball stops at the highest point
g = -9.8 m/s² (negative sign for upward motion)
h = maximum height reached by ball
therefore, eqn becomes:
2(-9.8m/s²)(h) = (0 m/s)² - (3.75 m/s²)²
<u>h = 0.2 m</u>
b)
To find out the initial speed to reach the hoop at height of 3.5 m, we again use 3rd eqn. of motion with h= 3.5 m - 2.5m = 1 m (taking launch point as reference), and Vo as unknown:
2(-9.8m/s²)(1 m) = (0 m/s)² - (Vo)²
(Vo)² = 19.6 m²/s²
Vo = √19.6 m²/s²
<u>Vo = 4.43 m/s</u>
Vo = (4.43 m/s)(1 s/1000 ms)(39.37 in/1 m)
<u>Vo = 0.174 in/ms</u>
<u />
Answer:
Solution
Explanation:
Solution:-
- The direction of motion of bus and car can be denoted by velocity vectors ( v1 and v2 ) respectively.
- On a page draw the velocity vector v1 vertically up denoting the direction of motion of bus from origin
- Similarly,draw the velocity vector v1 horizontally left denoting the direction of motion of car from origin.
- The force exerted by the car-bus interaction is always in the direction of motion.
- The force exerted by the bus is parallel to velocity vector as F1 and force exerted by the car is parallel to velocity vector as F2.
- The vector addition of of the two forces ( F1 and F2 ) will tell us the direction and magnitude of resultant force due to car-bus interaction.
- The resultant force will cause the car to be pushed off the road in the direction shown in the diagram.
