Answer:
Energy (I need one more brainlist can i has?)
Explanation:
- Nuclear fusion occurs when two light nuclei fuse together into a heavier nucleus
- Nuclear fission occurs when a heavy, unstable nucleus breaks apart into two or more lighter nuclei
In both processes, the mass of the products is always smaller than the mass of the initial nuclei. This means that part of the initial mass has been converted into something else: into energy, which is released in the process.
The amount of energy released in the process can be calculated by using the famous Einstein's equivalence:
where m is the difference between the mass of the product and the initial mass of the nuclei, and c is the speed of light.
Answer:
The value is 
Explanation:
From the question we are told that
The mass of each sphere is 
The length of the string is
The angle of with the vertical is 
The acceleration due to gravity is 
Generally the force acting between the forces is mathematically represented as

=> 
Generally from Pythagoras theorem the radius of the circular curve created by the force is

=> 
=>
=> 
=> 
=> 
Answer:
ANSWERS ARE 100 % correct
Explanation:
trust me
Answer:
a)
= 0.25 m / s b) u = 0.25 m / s
Explanation:
a) To solve this problem let's start with the conservation of the moment, for this we define a system formed by the ball plus the dog, in this case all the forces are internal and the moment is conserved
We will write the data
m₁ = 0.40 kg
v₁₀ = 9.0 m / s
m₂ = 14 kg
v₂₀ = 0
Initial
po = m₁ v₁₀
Final
= (m₁ + m₂) vf
po = pf
m₁ v₁₀ = (m₁ + m₂) 
= v₁₀ m₁ / (m₁ + m₂)
= 9.0 (0.40 / (0.40 +14)
= 0.25 m / s
b) This is the reference frame of the center of mass of the system in this case the speed of this frame is the speed of the center of mass
u = 0.25 m / s
In the direction of movement of the ball
c) Let's calculate the kinetic energy in both moments
Initial
K₀ = ½ m₁ v₁₀² +0
K₀ = ½ 0.40 9 2
K₀ = 16.2 J
Final
= ½ (m₁ + m₂)
2
= ½ (0.4 +14) 0.25 2
= 0.45 J
ΔK = K₀ - 
ΔK = 16.2-0.445
ΔK = 1575 J
These will transform internal system energy
d) In order to find the kinetic energy, we must first find the velocities of the individual in this reference system.
v₁₀’= v₁₀ -u
v₁₀’= 9 -.025
v₁₀‘= 8.75 m / s
v₂₀ ‘= v₂₀ -u
v₂₀‘= - 0.25 m / s
‘=
- u
= 0
Initial
K₀ = ½ m₁ v₁₀‘² + ½ m₂ v₂₀‘²
Ko = ½ 0.4 8.75² + ½ 14.0 0.25²
Ko = 15.31 + 0.4375
K o = 15.75 J
Final
= ½ (m₁ + m₂) vf’²
= 0
All initial kinetic energy is transformed into internal energy in this reference system
Yo sup??
The weight vector is usually drawn vertically downwards from the centre of the body.
It can be respectively resolved as well.
Hope this helps