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Mrrafil [7]
3 years ago
8

A gold cube is 170.00 mm long, 20.00 cm wide, and 0.99 m thick. If gold has a

Chemistry
1 answer:
GaryK [48]3 years ago
6 0

Answer:

Explanation:

There's 2 steps: first find the volume then the mass

volume=lwh

convert 20 cm to mm: 20x10=200mm

volume=(170)(200)(0.99)

volume=33,660 mm

since the density is in cm cubed, convert 33,660 mm to cm

33,660/10=3366

density=mass/volume, rearrange to get mass=density x volume

mass=19.3 x 3366

mass=64963.8

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Consider the reaction: 2 H2O (g)-->2 H2 (g) + O2 (g). ΔH=483.6 Kj/mol. If 2 moles of H2O (g) are converted H2(g) and O2(g) ag
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<span>2 H2O(g) → 2 H2(g) + O2(g) </span>

<span>You can see that there are 2 moles of gas in the reactants and 3 moles of gas in the products. </span>

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<span>Since it is done under constant temp and pressure that means the volume change will be equal to the volume of 1 mole of gas </span>

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<span>The gas equation is </span>

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<span>- the gas constant is different for different units of temp and pressure (see wikki link) in this case temp and pressure are constant, and we want to put the result in an equation that has Joules in it, so we select 8.314 JK^-1mol^-1) </span>
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Oxidation number is defined as the number which is given to an atom when it looses or gains electron. When an atom looses electron, it attains a positive oxidation state. When an atom gains electron, it attains a negative oxidation state.

Oxidation state of the atoms in their elemental state is considered as 0. Hydrogen is present as gaseous state.

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Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: 0

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Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

Hence, the correct answer is 2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

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