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Oksanka [162]
3 years ago
9

À A car moves with an initial velocity of 18 m/s due north. Find the velocity of the car after 7 Os if

Physics
1 answer:
Nonamiya [84]3 years ago
3 0

Answer:

(a) v_f=28.5m/s

(b) v_f=7.5m/s

Explanation:

Hello.

(a) In this case since the car is moving at an initial velocity of 18 m/s due north, the final velocity is computed considering the acceleration as positive since it is due north as well:

v_f=v_0+at=18m/s+1.5m/s^2*7s\\\\v_f=28.5m/s

(b) In this case, since the car is moving due north by the acceleration is due south it is undergoing a slowing down process, thereby the acceleration is negative therefore the final velocity turns out:

v_f=v_0+at=18m/s-1.5m/s^2*7s\\\\v_f=7.5m/s

Best regards.

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Answer:

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Explanation:

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work done = ΔK.E ( change in Kinetic energy )  ---- ( 1 )

<em>where :</em>

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( note : convert 1 year to seconds )

and ΔK.E = 1/2 mVf^2   given ; m = 1200 kg  and initial V = 0

<u>back to equation 1 </u>

473040000 * 10^6  = 1/2 mv^2

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<u>i) Determine how fast the rocket is ( acceleration of the rocket )</u>

a = Vf / t

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  = 0.0282 m/s^2

<u>ii) determine distance travelled by rocket </u>

Vf^2 - Vi^2 = 2as

Vi = 0

hence ; Vf^2 = 2as

s ( distance ) =  Vf^2 / ( 2a )

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Given

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