1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Oksanka [162]
3 years ago
9

À A car moves with an initial velocity of 18 m/s due north. Find the velocity of the car after 7 Os if

Physics
1 answer:
Nonamiya [84]3 years ago
3 0

Answer:

(a) v_f=28.5m/s

(b) v_f=7.5m/s

Explanation:

Hello.

(a) In this case since the car is moving at an initial velocity of 18 m/s due north, the final velocity is computed considering the acceleration as positive since it is due north as well:

v_f=v_0+at=18m/s+1.5m/s^2*7s\\\\v_f=28.5m/s

(b) In this case, since the car is moving due north by the acceleration is due south it is undergoing a slowing down process, thereby the acceleration is negative therefore the final velocity turns out:

v_f=v_0+at=18m/s-1.5m/s^2*7s\\\\v_f=7.5m/s

Best regards.

You might be interested in
There is evidence that elephants communicate via infrasound, generating rumbling vocalizations as low as 14 Hz that can travel u
amid [387]

Answer:

L = 96.2 dB

Explanation:

As we know that the level of intensity is given as

\beta = 10Log(\frac{I}{I_o})

here we know

\beta = 104 dB

104 = 10Log(\frac{I}{10^{-12}})

I = 0.025 W/m^2

now the sound is travelling in all possible directions so we have

\frac{I_1}{I_2} = \frac{r_2^2}{r_1^2}

\frac{0.025}{I_2} = \frac{10^2}{4.1^2}

I_2 = 4.2 \times 10^{-3} W/m^2

now for level of sound we have

L = 10Log(\frac{4.2 \times 10^{-3}}{10^{-12}})

L = 96.2 dB

5 0
3 years ago
Which of the following processes could NOT be used to separate dissolved particles from the liquid in a solution? *
DIA [1.3K]

Answer:

Vaporation

Explanation:

In the vaporization or boiling, the passage of particles from the liquid state to the gaseous state occurs completely

5 0
4 years ago
Read 2 more answers
A long wire carrying a 5.0 A current perpendicular to the (xy)-plane intersects the x-axis at x = -2.00 cm. A second parallel wi
zimovet [89]

Answer:

a. 05cm from x axis

b. 8cm from x axis

Explanation:

If the net magnetic field is zero and the currents are in the same direction then the thanks point is between the currents i1 and i2 as show in the attachment below

a. Given that i1= 5A and i2=3A

Let assume the null point is xcm from current i1, then the null point will be (4-x)cm from current i2 since the total length is 4cm.

Now the magnetic field of the current i1 from the null point= to magnetic field of current i2 from the null point

B1=B2

μi1/2πx=μi2/2π(4-x)

i1/x=i2/(4-x)

5/x=3/(4-x)

20-5x=3x

8x=20

8x=2.5cm

since from the left of x axis is 2cm, then the null point is 2.5-2 which 0.5cm from the origin x axis.

The null point is 0.5cm from the origin x axis

b. If both current are flowing in opposite direction, the null point lies outside of the current.

Then with same analysis let assume the first current i1 is xcm from the null point and since the total length is 4cm the second current i2 will be (x-4)cm from the null point.

Also the magnetic field of the current i1 from the null point = to magnetic field of current i2 from the null point

B1=B2

μi1/2πx=μi2/2π(x-4)

i1/x=i2/(x-4)

5/x=3/(x-4)

5x-20=3x

2x=20

x=10cm.

This shows that the distance of the null point from current i1 is 10cm and the current i1 is 2cm from the x axis, then the null point is 10-2=8cm from the origin x axis.

The null point is 8cm from the x axis.

Check the attachment to see the diagram of the current and the null points

6 0
3 years ago
The gravitational attraction between a 20 kg cannonball and a 0.002 kg
Naya [18.7K]

Answer:

2.966\times 10^{-11}\ N

Explanation:

Given:

Mass of the cannonball (M) = 20 kg

Mass of the marble (m) = 0.002 kg

Distance between the cannonball and marble (d) = 0.30 m

Universal gravitational constant (G) = 6.674\times 10^{-11}\ m^3 kg^{-1} s^{-2}

Now, we know that, the gravitational force (F) acting between two bodies of masses (m) and (M) separated by a distance (d) is given as:

F=\dfrac{GMm}{d^2}

Plug in the given values and solve for 'F'. This gives,

F=\frac{(6.674\times 10^{-11}\ m^3 kg^{-1} s^{-2})\times (20\ kg)\times (0.002\ kg)}{(0.30\ m)^2}\\\\F=\frac{6.674\times 20\times 0.002\times 10^{-11}\ m^3 kg^{-1+2} s^{-2}}{0.09\ m^2}\\\\F=2.966\times 10^{-11}\ kg\cdot m\cdot s^{-2}\\\\F=2.966\times 10^{-11}\ N.........(1\ N = 1\ kg\cdot m\cdot s^{-2})

The same force is experienced by both cannonball and marble.

Therefore, the gravitational  force of the marble is 2.966\times 10^{-11}\ N

3 0
3 years ago
What energy is calculated from an object’s mass, height, and the acceleration due to gravity? A. elastic kinetic B. elastic pote
Alex777 [14]

Answer: C. gravitational kinetic

Explanation: Gravitational potential energy is the energy calculated from an object's mass height and the acceleration due to gravity. The gravitational potential energy is the energy an object has as a result of the position of the object in a gravitational field.

3 0
3 years ago
Read 2 more answers
Other questions:
  • Think about Newton's 2nd Law, Force equals mass times acceleration. Liz puts a 1 kg weight and a 10 kg weight on identical wagon
    14·2 answers
  • *PLEASE HELP WILL GIVE BRAINLIEST*
    10·1 answer
  • Based on how stars are named, which star is probably brightest
    11·2 answers
  • A carbon resistor is to be used as a thermometer. On a winter day when the temperature is 4.00 ∘C∘C, the resistance of the carbo
    11·1 answer
  • A slender rod is 90.0 cm long and has mass 0.120 kg. A small 0.0200 kg sphere is welded to one end of the rod, and a small 0.080
    14·1 answer
  • How do you calculate the coefficient of friction?​
    9·1 answer
  • From the small number of impact craters on ____, planetary geologists suspect that virtually all its original surface has been c
    15·1 answer
  • If you are having a bad day, remember to stay positive! I pray that you pass a hard exam, quiz, test and get through depression,
    8·1 answer
  • If the evaporator outlet temperature on an r410A system is 50f and the evaporator superheat is 10f, what is the evaporating pres
    7·1 answer
  • Activity 1. Part A. Lat There Be Light
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!