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Nitella [24]
3 years ago
5

Oxygen is earth's most abundant element by volume in earth's?

Chemistry
1 answer:
agasfer [191]3 years ago
3 0
Oxygen is Earth's most abundant element by volume in Earth's Orbit
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What energy is needed to make evaporation happen
Stella [2.4K]
Heat energy is needed for evaporation to happen.
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3 years ago
How many grams of CuF2 are needed to make a 2.8 M solution
11111nata11111 [884]
Molarity is given as,

                              Molarity  =  Moles / Volume of Solution  ----- (1)

Also, Moles is given as,

                              Moles  =  Mass / M.mass

Substituting value of moles in eq. 1,

                              Molarity  =  Mass / M.mass × Volume

Solving for Mass,

                              Mass  =  Molarity × M.mass × Volume  ---- (2)

Data Given;

                  Molarity  =  2.8 mol.L⁻¹

                  M.mass  =  101.5 g.mol⁻¹

                  Volume  =  1 L (I have assumed it because it is not given)

Putting values in eq. 2,

                              Mass  =  2.8 mol.L⁻¹ × 101.5 g.mol⁻¹ × 1 L

                              Mass  =  284.2 g of CuF₂
5 0
3 years ago
Please help me it's just one question!
sashaice [31]

Answer:

hope this help

Explanation:

brainliest pls

6 0
3 years ago
How many liters of water vapor can be produced if 13.3 liters of methane gas (CH4) are combusted, if all measurements are taken
Pie
To get the number of liters of water vapor produced from the combustion of methane gas, we just need the stoichiometric ratio of water to methane which is 2:1. So the number of liters of water vapor from 13.3 liters of methane is 26.6 liters.
6 0
3 years ago
How many moles, kmols in: 100 g of CO2, 1 litre of ethyl alcohol of density 0.789 g/cm3 and a) 1.5m3 of O2 at 25°C and 1 atm. b)
Nutka1998 [239]

Explanation:

1) Mass of carbon dioxide = 100 g

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide =\frac{100 g}{44 g/mol}=2.273 moles

1 mol = 0.001 kmol

2.273 moles= 2.273 × 0.001 kmol = 2.273\times 10^{-3} kmol

2) 1 liter of ethyl alcohol of density 0.789 g/cm^3

Volume of ethyl alcohol ,V= 1 L = 1000 mL

Density of ethyl alcohol =d = 0.789 g/cm^3

1 cm^3=1 mL

Mass of ethyl alcohol = m

m=d\times V=0.789 g/cm^3\times 1000 mL=789 g

Molar mass of  ethyl alcohol = 46 g/mol

Moles of ethyl alcohol = \frac{789 g}{46 g/mol}=17.152 mol

17.152 mol=17.152\times 0.001 kmol=1.7152\times 10^{-4} kmol

3) Volume of oxygen gas,V =1.5 m^3=1500 L

1 m^3= 1000 L

Temperature of the gas = T= 25°C = 298.15 K

Pressure of the gas ,P= 1 atm

Moles of oxygen gas = n

PV=nRT

n=\frac{RT}{PV}=\frac{0.0821 atm L/mol K\times 298.15 K}{1 atm\times 1500 L}=0.01632 mol

0.01632 mol = 0.01632 × 0.001 kmol=1.632\times 10^{-5} kmol

4) Volume water in mixture = 1 L

Density of water =  1000 kg/m^3=\frac{1,000,000 g}{1000 L}=1000 g/L

Mass of water = 1000 g/L\times 1 L = 1000 g

Volume of alcohol = 2.5 L

Density of alcohol =  789 kg/m^3=\frac{789000 g}{1000 L}=789 g/L

Mass of alcohol = 789 g/L\times 2.5 L = 1972.5 g

Mass of mixture = 1000 g + 1972.5 g = 2972.5 g

Mass percentage of water :

\frac{1000 g}{2972.5 g}\times 100=33.64\%

Mass percentage of alcohol :

\frac{1972.5 g}{2972.5 g}\times 100=66.36\%

Moles of water :

n_1=\frac{1000 g}{18 g/mol}=55.55 mol

Moles of alcohol =

n_2=\frac{1972.5 g}{46 g/mol}=42.88 mol

Mole fraction of water :

\chi_1=\frac{n_1}{n_1+n_2}=\frac{55.55 mol}{55.55 mol+42.88 mol}=0.5644

Mole fraction of alcohol :

\chi_2=\frac{n_2}{n_1+n_2}=\frac{42.88 mol}{55.55 mol+42.88 mol}=0.4356

3 0
3 years ago
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