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Gnom [1K]
3 years ago
12

Two cylinders with the same mass density rhoC = 713 kg / m3 are floating in a container of water (with mass density rhoW = 1025

kg / m3). Cylinder #1 has a length of L1 = 20 cm and radius r1 = 5 cm. Cylinder #2 has a length of L2 = 10 cm and radius r2 = 10 cm. If h1 and h2 are the heights that these cylinders stick out above the water, what is the ratio of the height of Cylinder #2 above the water to the height of Cylinder #1 above the water (h2 / h1)? h2 / h1 =
Physics
1 answer:
Tanzania [10]3 years ago
5 0

Answer:

Explanation:

Given

density of cylinder is \rho _c=713 kg/m^3

Length of first cylinder is L_1=20 cm

radius r_1=5 cm

For cylinder 2 L_2=10 cm

r_2=10 cm

h_1 and h_2 are the height above water

E

as object is floating so its weight must be balanced with buoyant force

\rho _c\frac{\pi }{4}d_1^2L_1g=\rho _w\frac{\pi }{4}d_1^2(L_1-h_1)g----1

For 2nd cylinder

\rho _c\frac{\pi }{4}d_2^2L_2g=\rho _w\frac{\pi }{4}d_2^2(L_2-h_2)g----2

Dividing 1 and 2 we get

\frac{L_1}{L_2}=\frac{L_1-h_1}{L_2-h_2}

\frac{20}{10}=\frac{20-h_1}{10-h_2}

2h_2=h_1

\\\Rightarrow\frac{h_2}{h_1}=\frac{1}{2}                            

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