R=√20²+40²+2.20.40 cos 50
R=55 N
R/sin β = F/sin α
55/sin 50 = 40/sin α
α = 33°
Answer:
Explanation:
Given
Sphere A has a net charge of +5 Q
Sphere B has a net charge of -3 Q
Sphere C has a net charge of 7 Q
When sphere B is touched to sphere A then charge is redistributed among the sphere such that charge on each sphere is
Now sphere A and B has charge Q
When sphere A is touched to sphere C
Net charge after removal
Now sphere A and C has 4 Q charge
Now sphere C and B is touched
Net charge on C and B is given by
At the end of process charge on sphere A is 4Q
Charge on B and C is 2.5Q
Answer:
increase
Explanation:
According to Einstein's photoelectric equation; the energy of a photon striking a metal surface is related to the kinetic energy of the ejected photoelectron by the formula;
KE= hf - hfo
Where h is the planks constant, f and fo refer to the frequency of incident photon and the threshold frequency respectively.
Hence, we can clearly see from the foregoing that the kinetic energy of the ejected photoelectron is proportional to the frequency of the incident photon.
Hence, if the frequency of the incident photon is increased, the kinetic energy of the ejected photoelectron increases also.
Answer:
杰恩斯克克斯克奇沃伊斯克克斯克什德布德克什恩克恩德恩克恩茨克杰兹姆克斯恩斯姆斯姆德恩德姆德武伊乔奥斯克斯杰德布德赫德夫赫富伊什杰吉迪赫德赫夫赫德