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xeze [42]
3 years ago
6

A student receives 83.2 points, 44.6 points, 74.4 points, and 52.3 points on each of four tests. Determine the student's test av

erage with the correct significant digits.
Chemistry
1 answer:
kow [346]3 years ago
3 0

Answer:

The average is 63.6

Explanation:

<u>Step 1: Calculate the total points of all tests together</u>

The total of the 4 tests is : 83.2 points + 44.6 points + 74.4 points + 52.3 points = 254.5 points

<u>Step 2: Calculate the average points</u>

We have 4 tests so we divide the total number by 4

254.5 points  / 4 = 63,625 points

<u>Step 3: take significant digits into account</u>

<em><u>Sum or difference :</u></em><u> </u>Add or subtract in the normal way, then round the answer to the LEAST number of places to the decimal point of any number in the problem

⇒ in this case : 83.2 + 44.6 + 74.4 + 52.3 = 254.5

<u>Multiplication and division:</u> the answer is reported in such a way that it reflects the reliability of the least precise operation. Your answer cannot be MORE precise than the least precise measurement.

254.5 / 4 = 63.6

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The analysis of a compound gives the following percent composition by mass: C: 52.14 percent; H: 9.946 percent; S: 12.66 percent
wariber [46]

Answer:

C11H25SO4

Explanation:

The total mass of the compound is 253.4 g, so, the mass of each element will be:

C: 52.14% of 253.4 = 0.5214x253.4 = 132.12 g

H: 9.946% of 253.4 = 0.09946x253.4 = 25.20 g

S: 12.66% of 253.4 = 0.1266x253.4 = 32.08 g

O: 25.26% of 253.4 = 0.2526x253.4 = 64.00 g

The molar mass are: C = 12 g/mol, H 1 g/mol, S = 32 g/mol, and O = 16 g/mol

So, to know how much moles will be, just divide the mass calculated above for the molar mass:

C: 132.12/12 = 11 moles

H: 25.20/ 1 = 25 moles

S: 32.08/32 = 1 mol

O: 64.00/16 = 4 moles

So the molecular formula is C11H25SO4

3 0
2 years ago
75.0 grams of MgCl, is dissolved in 500.0 g of water, density 1.00 g/ml. What is the MOLALITY of this solution?
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C

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8 0
2 years ago
A city in Laguna generates 0.96 kg per capita per day of Municipal Solid Waste (MSW). Makati City in Metro Manila generates 1.9
mamaluj [8]

Answer:

i) amount of MSW generated:

Laguna: 19200 Kg/day

Makati: 38000 Kg/day

ii) number of trucks to collect twice weekly:

Laguna: 3 trucks

Makati: 5 trucks

iii) volume of MSW in tons that enter landfill/week:

Laguna: 147.84 ton/week

Makati: 292 ton/week

Explanation:

i) Laguna: 0.96 Kg person / day of MSW * 20000 = 19200 Kg MSW / day

⇒ Laguna: 19200 Kg/day * ( 7day/ week ) = 134400 Kg/week

Makati: 1.9 Kg person / day of MSW * 20000 = 38000 Kg MSW / day

⇒ Makati: 38000 Kg/day * ( 7day/week ) = 266000 Kg/week

ii)  truck capacity = 4.4 ton * ( Kg / 0.0011 ton ) = 4000 Kg

⇒ quote/day = 4000 Kg * 0.75 = 3000 Kg

⇒ loads/day = 2 * 3000 kg = 6000 Kg

⇒ operate/week = 5 * 6000 Kg = 30000 Kg

∴ Laguna:  number of trucks needed/week= 134400 / 30000  = 4.48 ≅ 5 trucks

⇒ number of trucks to collect twice weekly = 5 / 2 = 2.5 ≅ 3 trucks

∴ Makati : number of trucks needed/week = 266000 / 30000 = 8.86 ≅ 9 trucks

⇒ number of trucks to collect twice weekly = 9 / 2 = 4.5 ≅ 5 trucks  

iii) enter landfill/week:

Laguna: 134400Kg MSW/week * ( 0.0011 ton/Kg ) = 147.84 ton/week

Makati: 266000Kg MSW/week * ( 0.0011 ton/Kg ) = 292 ton/week

4 0
2 years ago
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