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bezimeni [28]
3 years ago
5

PLEASE HELP ME What does a moving charge experience when it is near a magnetic field? static friction gravity a stationary charg

e a force
Physics
1 answer:
attashe74 [19]3 years ago
6 0

<u><em>A moving charge experiences a force as it moves close to a magnetic field present in a region.</em></u>

Explanation:

A charged particle when moves near a magnetic field is forced to move in a circular path. If there is a straight moving charged particle enters the region of the magnetic field, it's path is changed from straight path to the curved path.

The motion of the charged path inside or near the magnetic field will be a circular path and this circular path is due to the force experienced by the charged particle in the magnetic field.

The force experienced by the a charged particle as it moves near the magnetic field is termed as the Lorentz force. The expression for the Lorentz force experienced by the charged particle in the magnetic field is given by:

\boxed{F_m=Q(\overrightarrow{v}\times\overrightarrow{B})}

Here, F_m is the magnetic force, Q is the amount of charge, \overrightarrow{v} is the velocity vector and \overrightarrow{B} is the magnetic field intensity in the region.

Thus, <u><em>A moving charge experiences a force as it moves close to a magnetic field present in a region.</em></u>

Learn More:

1. Which one is true for the electromagnetic spectrum brainly.com/question/1619496

2. What is the current in resistor R2 brainly.com/question/3051098

3. Average current denisty of a linear wire brainly.com/question/10597501

Answer Details:

Grade: High School

Subject: Physics

Chapter: Electromagnetism

Keywords:

moving, charge, straight, circular, path, magnetic, field, amount, force, velocity, intensity, Lorentz, expression, stationary.

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\frac{\mu_oi_1}{2\pi x}=\frac{\mu_oi_2}{2\pi(4-x)}\\\\5/x=\frac{3.5}{4-x}\\\\x=2.35cm\\\\N=2.35-2=0.35cm

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#For the magnetic fields to be zero,the fields of both wires should be equal and opposite.They are only opposite in outside the wires:

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\frac{\mu_oi_1}{2\pi(4+ x)}=\frac{\mu_oi_2}{2\pi x}\\\\5/(4+x)=\frac{3.5}{x}\\\\x=9.33cm\\\\N=9.33+2=11.33cm

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