1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Kamila [148]
3 years ago
11

Water is the working fluid in a regenerative Rankine cycle with one open feedwater heater. Steam enters the turbine at 1400 lbf/

in^2 and 1000F and expands to 120 lbf/in^2, where some of the steam is extracted and diverted to the open feedwater heater operating at 120 lbf/in^2. The remaining steam expands through the second-stage turbine to the condenser pressure of 2 lbf/in^2. Each turbine stage and both pumps have isentropic efficiencies of 85%. Flow through the condenser, open feedwater heater, and steam generator is at constant pressure. Saturated liquid exits the open feedwater heater at 120 lbf/in^2. The net power output of the cycle is 1 x 10^9 Btu/h. Determine for the cycle
(a) the mass flow rate of steam entering the first stage of the turbine, in lb/h.

(b) the rate of heat transfer, in Btu/h, to the working fluid passing through the steam generator.

(c) the thermal efficiency.

Engineering
1 answer:
Ilya [14]3 years ago
4 0

Answer:

(a)The mass flow rate =

2.297×10^6 lb/HR

(b)the rate of heat transfer =2700.847×10^6Btu/hr

(c)thermal efficiency is 37.025%

Check attachments for calculation

You might be interested in
Is there a way to get the answers to a NCCER book test?
sergeinik [125]

Answer:

go on google and type NCEER book answers

3 0
3 years ago
You have been assigned to design an open cylindrical storage tank 4 meters tall with a diameter of 8 meters to be made out of A-
Katen [24]

Answer:

The required wall thickness is 1.506 \times 10^{-3} m

Explanation:

Given:

Fluid density \rho = 1200 \frac{kg}{m^{3} }

Diameter of tank d = 8 m

Length of tank l = 4 m

F.S = 4

For A-36 steel yield stress \sigma = 250 MPa,

Allowable stress \sigma _{allow} = \frac{\sigma}{F.S}

 \sigma _{allow} = \frac{250}{4} = 62.5 MPa

Pressure force is given by,

 P = \rho gh

 P = 1200 \times 9.8 \times 4

P = 47088 Pa

Now for a vertical pipe,

\sigma _{allow} = \frac{Pd}{4t}

Where t = required thickness

 t = \frac{Pd}{4 \sigma _{allow} }

 t = \frac{47088 \times 8 }{4 \times 62.5 \times 10^{6} }

t = 1.506 \times 10^{-3} m

Therefore, the required wall thickness is 1.506 \times 10^{-3} m

8 0
3 years ago
HELP ME PLEASE RN
IRISSAK [1]

Answer:

information

Explanation:

see picture

8 0
3 years ago
A nozzle receives an ideal gas flow with a velocity of 25 m/s, and the exit at 100 kPa, 300 K velocity is 250 m/s. Determine the
Margaret [11]

Given Information:

Inlet velocity = Vin = 25 m/s

Exit velocity = Vout = 250 m/s

Exit Temperature = Tout = 300K

Exit Pressure = Pout = 100 kPa

Required Information:

Inlet Temperature of argon = ?

Inlet Temperature of helium = ?

Inlet Temperature of nitrogen = ?

Answer:

Inlet Temperature of argon = 360K

Inlet Temperature of helium = 306K

Inlet Temperature of nitrogen = 330K

Explanation:

Recall that the energy equation is given by

$ C_p(T_{in} - T_{out}) = \frac{1}{2} \times (V_{out}^2 - V_{in}^2) $

Where Cp is the specific heat constant of the gas.

Re-arranging the equation for inlet temperature

$ T_{in}  = \frac{1}{2} \times \frac{(V_{out}^2 - V_{in}^2)}{C_p}  + T_{out}$

For Argon Gas:

The specific heat constant of argon is given by (from ideal gas properties table)

C_p = 520 \:\: J/kg.K

So, the inlet temperature of argon is

$ T_{in}  = \frac{1}{2} \times \frac{(250^2 - 25^2)}{520}  + 300$

$ T_{in}  = \frac{1}{2} \times 119  + 300$

$ T_{in}  = 360K $

For Helium Gas:

The specific heat constant of helium is given by (from ideal gas properties table)

C_p = 5193 \:\: J/kg.K

So, the inlet temperature of helium is

$ T_{in}  = \frac{1}{2} \times \frac{(250^2 - 25^2)}{5193}  + 300$

$ T_{in}  = \frac{1}{2} \times 12  + 300$

$ T_{in}  = 306K $

For Nitrogen Gas:

The specific heat constant of nitrogen is given by (from ideal gas properties table)

C_p = 1039 \:\: J/kg.K

So, the inlet temperature of nitrogen is

$ T_{in}  = \frac{1}{2} \times \frac{(250^2 - 25^2)}{1039}  + 300$

$ T_{in}  = \frac{1}{2} \times 60  + 300$

$ T_{in}  = 330K $

Note: Answers are rounded to the nearest whole numbers.

5 0
3 years ago
A college student volunteers with the elderly in a hospice program and discovers her clients complain of dry skin. She has an id
daser333 [38]

Answer:

D

Explanation: She hopes to be able to make this, however she hasn't yet...therefore she is thinking of a concept and it's development

3 0
3 years ago
Read 2 more answers
Other questions:
  • What should the resistance value be on a size 5 motor starter coil
    14·1 answer
  • The ratio of the weight of a substance to the weight of equal volume of water is known as a) Density b) specific gravity c) spec
    8·1 answer
  • A spherical, stainless steel (k 16 W m1 K-1) tank has a wall thickness of 0.2 cm and an inside diameter of 10 cm. The inside sur
    12·1 answer
  • Line layout is also called ......​
    5·1 answer
  • You are given that kc = 10-1 kg eq-1 min-1, ku = 10-3 kg2 eq-2 min-1 and [A]0 = 10 eq kg-1, where kc is the rate constant for a
    15·1 answer
  • A logic chip used in a computer dissipates 3 W of power in an environment at 120°F, and has a heat transfer surface area of 0.08
    11·1 answer
  • Assume a steel pipe of inner radius r1= 20 mm and outer radius r2= 25 mm, which is exposed to natural convection at h = 50 W/m2.
    12·1 answer
  • 3. Technician A says passive permanent
    5·1 answer
  • The displacement of a certain object is described by y(t) = 23 sin 5t, where t is measured in seconds. Compute its period and it
    9·1 answer
  • A dual-fluid heat exchanger has 10 lbm/s water entering at 100 F, 20 psia and leaving at 50 F, 20 psia. The other fluid is glyco
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!