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frozen [14]
4 years ago
11

Next weekend you are going to Eleanor Rigby’s house to fix her grandfather clock that is a bit slow. Based on what you have lear

ned about pendulums, how will you fix her slow clock?
Physics
1 answer:
Bumek [7]4 years ago
8 0

Answer:

By pushing the pendulum Bob up so it moves faster

Explanation:

In pendulum physics the length of the pendulum Bob determines the speed of the clock. So since the grandfather's clock is slow it means the Bob is has moved down so to move it up you have to achieve this by adjusting the but upwards thereby making the clock move faster.

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I NEED HELP ASAP!! I NEED IT BEFORE TOMORROW!! D: 10pts+5pts!
Wewaii [24]
9. Compounds can form from two nonmetals by sharing their electrons in a
C) covalent

11. An atom that has an excess positive or negative electrical charge caused by the loss or addition of an electron is called a(n) ______.
B) ion

5 is either A or C
4 0
3 years ago
That's because helium molecules are not packed together as densely as air molecules are. It is this simple reason that helium ba
Zinaida [17]

Answer:

Because the molecules are not packed together as much than the air, in a fixed volume of helium there are fewer particles than in the same fixed volume of air.

This means that the mass of the fixed volume of helium is smaller than the one of air, and then the density, defined as mass/volume, is also smaller.

This is why the balloon floats, because the air is denser, it tries to go down, pushing the ballon upside.

The case is similar for a piece of metal in water, as the metal is way denser than the water, the metal will sink, but for something not as dense, like a balloon with air, the balloon will remain in the surface of the water.

5 0
4 years ago
Is what flows and carries energy in a circuit
xenn [34]

The correct answer to this Electric current.

7 0
3 years ago
a person carries a plank of wood 2.00 m long with one hand pushing down on it at one end with a force f1 and the other hand hold
yKpoI14uk [10]

The magnitudes of forces at F₁ and F₂ are :

F₁ = 3924 N

F₂ = 4120.2 N

We know that force is the amount of strength required to move a body. The magnitude of force is the sum of all the strengths applied on the body which is exerted by each force together on a particular body.

Given,

Length of plank = 2 m

Force on one end = F₁

Force on the other end = F₂

F₂ is applied to a point which is 0.5 m from the other end

Mass of plank = 20 kg.

Now let us calculate the magnitudes of the forces applied:-

1) Balance of angular momentum around the end where F₁ is applied.

F₂ × 0.5m - F₁ × 0 = mass × g × 1m

⇒ F₂ × 0.5 m= 20 kg × 9.81 m/s² × 1 m = 1,962 N×m

F₂ = 196.2 Nm / 0.5m = 3,924 N

2) Balance of forces

F₁ - F₂ = mg

F₁ = F₂ + mg = 3,924N + 20kg (9.81 m/s²) = 4,120.2 N

Therefore the magnitude of force F₁ is 3924 N and of force F₂ is 4120.2 N.

To know more about force, refer: brainly.com/question/13191643

#SPJ4

3 0
1 year ago
Now the same particle is removed from the thread and placed over the center of a charged plate. Are there any conditions under w
labwork [276]

Answer:

changing the direction of the electric potential, we can get the particle to be in balance between the electric force, the weight and the thrust.

Explanation:

When the particle is removed from the wire, friction can be electrically charged, either with negative charges (extra electrons) or with positive charge by electron removal, in this case when the particle is between the condenser plates it experiences a force due to the electric field given by

          ΔV = E d

Where ΔV is the potential difference, d the distance between the plates and E the electric field.

In these cases we can use Newton's second law, where the acceleration is zero

                F_{e} –W + B = 0

                 F_{e} = W –B

                 q E = mg - ρ_air g V

dodne B is the hydrostatic thrust

if  we know the density of the particular

                   ρ_particle = m / V

                   m = ρ_particle V

We replace

                 q E = g v (ρ_particle - ρ_air)

Therefore, by changing the direction of the electric potential, we can get the particle to be in balance between the electric force, the weight and the thrust.

6 0
4 years ago
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