An experiment that involves using a Landsat satellite is given below;
Paddy lands detection through the use of Landsat-8 satellite images and object-based classification in cape town, South Africa.
<h3>What is the experiment about?</h3>
Rice is known to be one of the most vital food staples in a lot of countries, especially South Africa . Due to the irrigated rice production that tend to differs from other kinds of agricultural fields, this study was said to have created a paddy field mapping model via the use of phenological aspects, a lot of satellite sensor data, and also the use of object-based approach.
This study uses the phonological features of rice plants and also the use of an annual data regarding surface temperature (LST) to make the paddy map.
The core remote sensing data is made up of the yearly LST that is obtained from MODIS and multi-temporal Landsat-8 satellite imagery.
Based on the study, the total accuracy and kappa coefficient for the pixel-based classification method is seen to be 92% and 0.89.
Hence, An experiment that involves using a Landsat satellite is Paddy lands detection through the use of Landsat-8 satellite images and object-based classification in cape town, South Africa.
Learn more about Landsat satellite from
brainly.com/question/25656875
#SPJ1
Oxygen enters the blood Through your lungs
The largest is Mauna Loa on the Big Island of Hawaii; all the volcanoes in the Hawaiian Islands are shield volcanoes. There are also shield volcanoes, for example, in Washington, Oregon, and the Galapagos Islands
The speed of the ball moving is
![v = 3.94 \times 10 {}^{ - 25}m/s](https://tex.z-dn.net/?f=v%20%3D%203.94%20%5Ctimes%2010%20%7B%7D%5E%7B%20-%2025%7Dm%2Fs)
what is momentum?
The momentum p of a classical object of mass m and velocity v is given by pclassical =mv.
For photons with wavelength λ,this equation does not hold.Instead, the momentum of the Photon is given by p Photon = h/λ
where,h is the planck's constant.
The momentum of the red Photon is
given:
![h = 6.626 \times 10 {}^{ - 34}kgm {}^{2}/s(plancks \: constant)](https://tex.z-dn.net/?f=h%20%3D%206.626%20%5Ctimes%2010%20%7B%7D%5E%7B%20-%2034%7Dkgm%20%7B%7D%5E%7B2%7D%2Fs%28plancks%20%5C%3A%20constant%29)
![λ = 700 \times 10 {}^{ - 9} m(photons \: wavelength)](https://tex.z-dn.net/?f=%CE%BB%20%3D%20700%20%5Ctimes%2010%20%7B%7D%5E%7B%20-%209%7D%20m%28photons%20%5C%3A%20wavelength%29)
![p \: photons = \frac{6.626 \times 10 {}^{ - 34}kgm {} ^{2}/s }{700 \times 10 {}^{ - 9}m }](https://tex.z-dn.net/?f=p%20%5C%3A%20photons%20%3D%20%20%5Cfrac%7B6.626%20%5Ctimes%2010%20%7B%7D%5E%7B%20-%2034%7Dkgm%20%7B%7D%20%20%5E%7B2%7D%2Fs%20%7D%7B700%20%5Ctimes%2010%20%7B%7D%5E%7B%20-%209%7Dm%20%20%7D%20)
![= 9.47 \times 10 {}^{ - 28}kgm /s](https://tex.z-dn.net/?f=%20%3D%209.47%20%5Ctimes%2010%20%7B%7D%5E%7B%20-%2028%7Dkgm%20%2Fs)
since,the Photon and the ping-pong ball have the same momentum,we have
![pball = pphotons = \frac{6.626 \times 10 {}^{ - 34}kgm/s }{700 \times 10 {}^{ - 9} }](https://tex.z-dn.net/?f=pball%20%3D%20pphotons%20%3D%20%20%5Cfrac%7B6.626%20%5Ctimes%2010%20%7B%7D%5E%7B%20-%2034%7Dkgm%2Fs%20%20%7D%7B700%20%5Ctimes%2010%20%7B%7D%5E%7B%20-%209%7D%20%7D%20)
![pball = mv,m = 2.40 \times 10 {}^{ - 3}kg](https://tex.z-dn.net/?f=pball%20%3D%20mv%2Cm%20%3D%202.40%20%5Ctimes%2010%20%7B%7D%5E%7B%20-%203%7Dkg%20)
![v = 3.94 \times 10 {}^{ - 25} m/s](https://tex.z-dn.net/?f=v%20%3D%203.94%20%5Ctimes%2010%20%7B%7D%5E%7B%20-%2025%7D%20m%2Fs)
Therefore, if the red photon and the ping-pong ball have the same momentum, the ping-pong ball must have a speed of approximately
![v = 3.94 \times 10 {}^{ - 25}m/s](https://tex.z-dn.net/?f=v%20%3D%203.94%20%5Ctimes%2010%20%7B%7D%5E%7B%20-%2025%7Dm%2Fs)
learn more about momentum of photon from here: brainly.com/question/28197406
#SPJ4