Answer:
dV = 32.98 cm³
Explanation:
We know that
V = f ( h,r)
We also know that
Given that
h= 10 cm
d=10 cm , r= 5 cm
Thickness = 0.05 cm so dr = 0.05 cm
The metal in the top and the bottom is 0.2 cm thick so dh = 0.2 + 0.2 cm
dh = 0.4 cm
Now by putting the values
dV = 32.98 cm³
Answer:
ρ = 1469 kg/m³
Explanation:
given,
mass of statue = 0.4 Kg
density of statue = 8 x 10³ kg/m³
tension in the string = 3.2 N
density of the fluid = ?
Volume of the statue
V = 5 x 10⁻⁵ m³
W = ρ g V
W = ρ x 9.8 x 5 x 10⁻⁵
now, tension on the string will be equal to
T = mg - W
3.2 = 0.4 x 9.8 - ρ x 9.8 x 5 x 10⁻⁵
ρ x 9.8 x 5 x 10⁻⁵ = 0.72
ρ = 1469 kg/m³