Answer:
13.2% Mg, 86.8% Br
Explanation:
Mg has a molar mass of 24.31g/mol.
Bromine has a molar mass of 79.90 g/mol.
There is one mole of Mg and two moles of Br in the compound:
79.90x2 + 24.31 = 184.11
So the total molar mass of MgBr2 is 184.11.
A percent tells us a part of a whole, so we will divide each part of the mass into the whole mass.
24.31g Mg / 184.11g MgBr2 = .132
159.8g Br / 184.11g MgBr2 = .868
Multiply these decimals by 100 to make them into a percent.
.132 x 100 = 13.2% Mg
.868 x 100 = 86.8% Br
s =
100/13.75
s = 7.272727…/1
<span>s = 7.27m/s </span>
The reaction between <span>C3H7SH and oxygen can be illustrated using the following balanced equation:
</span>C3H7SH (l) + 6O2 (g) --> 3 CO2 (g) + SO2 (g) + 4 H2O (g)
From the balanced equation above, 6 moles of oxygen are required to produce 4 moles of water.
Therefore, to know the number of oxygen moles needed to produce 2.33 moles of water, all you have to do is cross multiplication as follows:
number of oxygen moles = (2.33*6) / 4 = 3.495 moles
Answer:
14 g.
Explanation:
- From the figure attached:
<em>the solubility of lead(II) nitrate, Pb(NO₃)₂, in 100 grams of water has a temperature of 30ºC is </em><em>(66 g).</em>
When beaker containing 80 grams of lead(II) nitrate, Pb(NO₃)₂, in 100 grams of water has a temperature of 30ºC.
<em>∴ The grams of the salt are undissolved, on the bottom of the beaker are </em><em>(14 g).</em>
Answer: 0.36 millimoles
Explanation:
According to ideal gas equation:
P = pressure of gas = 75.1 cm Hg = 0.98 atm (1cmHg = 10 mm Hg)
V = Volume of gas = (51.0-42.0) ml = 9.00 ml = 0.009 L
n = number of moles = ?
R = gas constant =
T = Temperature =
Thus 0.36 millimoles were removed from initial air sample