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Fed [463]
4 years ago
9

Pls help me with this question​

Physics
1 answer:
ryzh [129]4 years ago
8 0

Answer:

16 ms2 is the answer for this question

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If the velocity of a pitched ball has a magnitude of 47.0 m/s and the batted ball's velocity is 50.5 m/s in the opposite directi
Naya [18.7K]

Answer:

The magnitude of change in momentum of the ball is 97.5 m and impulse is also 97.5 m

Explanation:

Given:

Velocity of a pitched ball v _{i} = 47 \frac{m}{s}

Velocity of ball after impact v_{f}  = -50.5 \frac{m}{s}

From the formula of change in momentum,

  \Delta P = m (v_{f} -v_{i}  )

Here mass is not given in question,

Mass of ball is m

Change in momentum is given by,

\Delta P = m (-50.5 -47)

\Delta P = -97.5 m

Magnitude of change in momentum is

\Delta P = 97.5 m

And impulse is given by

 J = \Delta P

J = -97.5 m

So impulse and

Therefore, the magnitude of change in momentum of the ball is 97.5 m and impulse is also -97.5 m

6 0
3 years ago
When a warm air mass moves into an area where a cold air mass is located, it is called a(n) _____?
rusak2 [61]
It is called a warm front when a warm air mass moves into an area where a cold air mass is located based on the blanked sentence above. A warm front is a condition where a warm air mass is replacing a cold air in a place. The character of a warm front condition is an increasing in temperature of a place which is caused by the moving warm air mass<span>.</span>
8 0
4 years ago
Sunlight is made up of EM waves. True or False
GrogVix [38]

Answer:

true

Explanation:

7 0
3 years ago
The greater the mass of an object.
yKpoI14uk [10]

Answer:

Mass is the measure of an object's matter (what it's made up of). The greater an object's mass, the greater its gravitational force. The earth has a strong attracting force for objects with smaller mass (including the moon), and the sun has an attracting force on the earth and other planets in our solar system.

7 0
3 years ago
Read 2 more answers
What is the electric force acting between two charges of 0.0042 C and −0.0050 C that are 0.0030 m apart?
Black_prince [1.1K]

Answer:

A.−2.1 × 10^10 N

Explanation:

Using the formula;

E = k Q1Q2/d²

Where;

E is the electrical force  

k is the constant  

Q1, Q2 are the two charges  and

d is the distance between the two charges

Therefore;

E = (9 x 10^9) × (0.0042) × (-0.0050) / (0.0030)²  

 = -2.1 x 10^10 N

Therefore; electrical force acting between the two charges is -2.1 x 10^10 N.

6 0
4 years ago
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