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Alchen [17]
3 years ago
12

For the radial speed of an astronomical object to be determined, what must the object’s spectrum contain?

Physics
2 answers:
Ainat [17]3 years ago
5 0

Answer:

Either absorption or emission lines

Explanation:

For the radial speed of an astronomical object to be determined with a Doppler shift, what must we be able to see in the object's spectrum, Either absorption or Emission lines.

Asorption and Emission line explained below;

  • Absorption lines are usually seen as dark lines, or lines of reduced intensity, on a continuous spectrum.
  • An emission line will appear in a spectrum if the source emits specific wavelengths of radiation.

Alona [7]3 years ago
4 0

Answer:

The object's spectrum must contain a Doppler shift

Explanation:

This is because, the radial speed of the object is determined from the absorption and emission spectral lines.

The object can either be "blue shifted" or "red shifted". This blue or red shift helps us determine the radial speed of the object.

If the astronomical object moves towards us, it is blue shifted and if it moves away from us, it is red shifted.

This extra shift in its wavelength can thus be used to determine the radial speed of the astronomical object.

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<u>Answer:</u>

<em>The amount of water entering the earth through precipitation is equal to the amount of water leaving earth through transpiration.</em>

<u>Explanation:</u>

Rates of precipitation and evaporation vary widely according to regions and seasons. But in a global scale the rates are equal. Thus the total amount of earth’s water maintains its constancy even though there is a continuous change in forms of water.

Evaporation and transpiration are the forms in which Water leaves the earth and it returns to the earth in various forms of precipitation like rain, snow, dew, fog etc. This water then reaches ocean and land. The water that reaches the land flows as surface run off into rivers and water bodies or seep into the ground replenishing the ground water table.

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A man on the Moon observes two spaceships coming toward him from opposite directions at speeds of 0.600c and 0.600c. What is the
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Answer:

If we use the equation for the transformation of velocities for moving frames:

v' = (v - u) / (1 - u * v / c^2) where we measure the speed of v' approaching from the left where v is in a frame moving at -u towards v'

v' = (.6 c - (-.6 c)) / (1 - (-.6 c) * .6 c / c^2) = 1.2 c / (1 + .6 * .6)

or v' = 1.2 c / (1 + .36) = .88 c

v is approaching from the left at .6 c in the reference frame and the other frame approaches from the right at -.6 c with speed u  (-.6 c) and we measure the speed of v as seen in the frame moving to the left

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The magnetic field or force seems to be associated with the lineup of____________ within the magnet.
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The magnetic field or force seems to be associated with the lineup of electrons withim the magnet
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3 years ago
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select the example that best describes a renewable resource. a. all the houses built in the new neighborhood had natural gas ava
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A dragster starts from rest and travels 1/4 mi in 6.80 s with constant acceleration. What is its velocity when it crosses the fi
Ahat [919]
<h2>Its velocity when it crosses the finish line is 117.65 m/s</h2>

Explanation:

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 0 m/s

        Acceleration, a = ?

        Time, t = 6.8 s    

        Displacement, s = 1/4 mi =    400 meters

     Substituting

                      s = ut + 0.5 at²

                      400 = 0 x 6.8 + 0.5 x a x 6.8²

                      a = 17.30 m/s²

Now we have equation of motion v = u + at

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     Final velocity, v = ?

     Time, t = 6.8 s

      Acceleration, a = 17.30 m/s²

     Substituting

                      v = u + at  

                      v = 0 + 17.30 x 6.8

                      v = 117.65 m/s

Its velocity when it crosses the finish line is 117.65 m/s

6 0
3 years ago
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