The plane takes 4.76 s to reach the end of the runway
Explanation:
The motion of the airplane is a uniformly accelerated motion (=at constant acceleration), therefore we can solve the problem by using the following suvat equation:
![s=ut+\frac{1}{2}at^2](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2)
where
s is the distance covered
u is the initial velocity
t is the time elapsed
a is the acceleration
In this problem, we have:
s = 102 m is the lenght of the runway
u = 0 is the initial velocity of the airplane
is its acceleration
Solving for t, we find the time needed to reach the end of the runway:
![t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(102)}{9.0}}=4.76 s](https://tex.z-dn.net/?f=t%3D%5Csqrt%7B%5Cfrac%7B2s%7D%7Ba%7D%7D%3D%5Csqrt%7B%5Cfrac%7B2%28102%29%7D%7B9.0%7D%7D%3D4.76%20s)
Learn more about accelerated motion:
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