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IRISSAK [1]
3 years ago
8

What is the volume of the cylinder with a diameter of 16ft and height of 10ft?

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
7 0
A=2*π*r*h+2*π*r^2

 r = 16/2 = 8

using 3.14 for π since you don't say what to use

2x3.14x8x10 = 502.4

2x3.14x8^2 = 401.92

401.92 + 502.4 = 904.32 cubic ft.

 Round answer as needed

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so if perimiter is 100 then one side is 100/5 or 20
area will be \frac{20^2}{4}\sqrt{5(5+2\sqrt{5})}≈<span>688.2 square yards

2. area of a hexagon when 1 side is length x is \frac{3x^2\sqrt{3}}{2}
so if permiter is 100 then length of one side is 100/6 or about 16.666666666666
the area will be \frac{3(16.6666666)^2\sqrt{3}}{2}≈721.7 square yards

3. area of a regular octagon with side lenghts x is 2(1+\sqrt{2})x^2
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3 0
3 years ago
Problem is Sin38-cos52
Paha777 [63]
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3 years ago
Given the following perfect square trinomial, fill in the missing term<br> 4x2 + ___x + 49
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Step-by-step explanation:

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3 years ago
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Solve for the missing side to the nearest tenth.<br> 19<br> X<br> 51
telo118 [61]

Answer:

<em>x = 30.2 units</em>

Step-by-step explanation:

<u>Trigonometric Ratios</u>

The ratios of the sides of a right triangle are called trigonometric ratios.

Selecting any of the acute angles, it has an adjacent side and an opposite side. The trigonometric ratios are defined upon those sides and the hypotenuse.

The given right triangle has an angle of measure 51° and its adjacent leg has a measure of 19 units. It's required to calculate the hypotenuse of the triangle.

We use the cosine ratio to calculate x:

\displaystyle \cos\theta=\frac{\text{adjacent leg}}{\text{hypotenuse}}

\displaystyle \cos 51^\circ=\frac{19}{x}

Solving for x:

\displaystyle x=\frac{19}{\cos 51^\circ}

\displaystyle x=\frac{19}{0.6293}

x = 30.2 units

3 0
3 years ago
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